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3 years ago

Help!

Physics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

factory:

-mechanical energy

-nuclear energy

-gravitational energy

Explanation:

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Define impulse and momentum.<br>No spam

Doss [256]

Impulse: a certain amount of force you apply for an amount of time.

Impulse: F*t where F= Force & t=time

Momentum: increasing forward motion.

A ball rolling down a slide gains momentum

p=mv where m=mass and v=velocity

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2 years ago

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la

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Force, newtons 3rd law of motion stated for every action there is an equal and opposite reaction

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3 years ago

in a cricket match there are 5000 spectators counted 10 by 10 the number of significant figure in the measurement will be

BabaBlast [244]

Answer:

$\boxed{3 \ Significant \ figures}$

Explanation:

Total spectators = 5000

Counted by the groups of ten, So at last the result will be:

=> 5000/10 = 500

Significant figures in 500 are 3

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3 years ago

Are you better off in an accident where the hood is

horsena [70]

Answer:

you would be better off if the car bounced backwards

Explanation:

because if the hood was dismembered than you have a high chance of very bad injury but if it is just bounced back you would have less chance of getting hurt if properly sitting and seat belted.

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3 years ago

A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th

vladimir1956 [14]

Answer:

Force, $F=2.27\times 10^4\ N$

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

$F=\dfrac{-mu^2}{2d}$

$F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}$

F = -22713.92 N

$F=2.27\times 10^4\ N$

So, the magnitude of the force that stops the bullet is $2.27\times 10^4\ N$

7 0

3 years ago