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kherson [118]
3 years ago
12

What can be found by counting the number of troughs per second in a wave diagram? amplitude direction frequency speed wavelength

NextReset
Physics
2 answers:
nadezda [96]3 years ago
7 0
Frequency hope this helps
Nutka1998 [239]3 years ago
6 0
The period T is time it takes for one complete cycle or from "trough to trough" so the reverse is trough per sec = 1/T = frequency
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mr_godi [17]

Answer:

what is your exact question.

5 0
3 years ago
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A 20 cm square frame that can rotate about the 00' axis is placed in a homogeneous magnetic field with 0.5T induction directed v
IRISSAK [1]

The solution to this task is f00king Dis.

6 0
3 years ago
Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s
muminat

Answer:

Acceleration = 10.06 m/s²

Explanation:

1 mile = 1.6093km

1609.3m = 1 mile

1 m = \frac{1}{1609} mile

50.0 miles/hour = \frac{50 * 1609.3}{60 * 60} m/s

                          = 22.35m/s

from equation

S = Ut + 1/2 at²

v = U + at

22.35 = 0 + a * 2.22

a = 22.35 ÷ 2.22

= 10.06 m/s²

4 0
3 years ago
1. Which cell organelle is popularly known as power house of the cell. Why?
MrRissso [65]
The mitochondria is the powerhouse of the cell because it takes nutrients and breaks it down to provide energy for the cell.
5 0
3 years ago
The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
3 years ago
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