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Andrew [12]
3 years ago
14

A piece of tin has a mass of 16.52 g and a volume of 2.26 cm2 what is the density of tin?

Chemistry
1 answer:
ioda3 years ago
8 0
M/V=D
16.52/2.26=D
Density=6.86 g/cm^3
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A book sits motionless on a table. Which statement is true? Group of answer choices There are no forces acting on the book. The
Katena32 [7]

Answer:

The forces acting on the book are balanced by each other.

6 0
2 years ago
Name the following alkyne.<br> Please help me &lt;3
Alexandra [31]

Answer:

D. 7-methyl-3-octyne

Explanation:

1) Identify the parent chain and name it like an alkane.

• The longest chain of carbons, which consists of the functional group (which is the alkyne group in this case: C≡C).

• There are 8 carbons in the longest chain, so it is called an octane.

2) Now, identify the location of the functional group.

• The location number of the functional group should be as low as possible. Thus although we could count from the right, we start counting from the left since the functional group is closer to the left. From the left, the functional group would be at carbon 8 while from the left, it is on carbon 3.

• Replace 'ane' with 'yne' in octane for the alkyne group.

• This would give us 3-octyne.

3) Lastly, add in the name of the branch.

• Here we have one branch, -CH₃. This is read as methyl.

• Identify the location number of the branch by counting the number of carbons in the same direction as when we counted the location number of the functional group. The methyl branch has a location number of 7.

• Adding the name of the branch before the parent chain, we would arrive at 7-methyl-3-octyne as the IUPAC name of the alkyne.

Further Explanation:

A) This option is incorrect as there are only 8 carbons in the parent chain. Although there are 9 carbons in total, the 9th carbon is taken care of in '7-methyl'.

B) Location number of the functional group should be as low as possible, so start counting the number of carbons from the left!

C) Since the functional group is an alkyne, the word 'octane' should be 'octyne' instead.

8 0
3 years ago
How many molecules are present in each sample?8.55 mol SO2 :molecules SO2 0.603 mol CO :molecules CO a sample of NH3 containing
sineoko [7]

Answer:

- 5.15×10²⁴ molecules of sulfur dioxide

- 3.63×10²³ molecules of carbon monoxide

- 6.02×10²³ molecules of ammonia

Explanation:

We begin from the relation that 1 mol of molecules contains NA of molecules

NA = 6.02×10²³

Now, we make rules of three:

1 mol has 6.02×10²³ molecules, therefore:

8.55 moles of SO₂ must have (8.55 . NA) / 1 = 5.15×10²⁴ molecules of dioxide

0.603 moles of CO must have (0.603 . NA) / 1 = 3.63×10²³ molecules of monoxide

Avogadro's Number of molecules of NH₃ are 6.02×10²³ molecules of ammonia

3 0
3 years ago
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
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On the periodic table, periods are elements with similar
Vladimir [108]

Answer:

B.) Atomic Properties

can I have brainliest?

Have\\a\\nice\\day

<h2 />

3 0
3 years ago
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