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Andrew [12]
3 years ago
14

A piece of tin has a mass of 16.52 g and a volume of 2.26 cm2 what is the density of tin?

Chemistry
1 answer:
ioda3 years ago
8 0
M/V=D
16.52/2.26=D
Density=6.86 g/cm^3
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Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
vichka [17]

Answer:

3.

Explanation:

Hello,

In this case, it is convenient to write the chemical reaction as:

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

Which balanced turns out:

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Thus the number that should be in front of the calcium sulfate is 3 in order to balance the reaction.

Best regards.

8 0
3 years ago
What is the pressure in a 245 L tank that contains 5.21 kg of helium at 27 Celsius ​
Kitty [74]
<h2><u>Answer:</u></h2>

(These are not rounded to the correct decimal)

130.94 atm

13,266.6 kPa

99,571.4 mmHg

<h2><u>Explanation:</u></h2>

<u></u>

PV = nRT

V = 245L

P = ?

R = 0.08206 (atm) , 8.314 (kPa) , 62.4 (mmHg)

T = 273.15 + 27 = 300.15K

n = 1302.5 moles

How I found (n).

5.21kg x 1000g/1kg x 1 mole/4.0g = 1302.5 moles

Now, plug all the numbers into the equation.

Pressure in atm = (1302.5)(0.08206)(300.15) / 245 = 130.94 atm (not rounded to the correct decimal)

Pressure in kPa = (1302.5)(8.314)(300.15) / 245 = 13,266.6 kPa (not rounded to the correct decimal)

Pressure in mmHg = (1302.5)(62.4)(300.15) / 245 = 99,571.4 mmHg (not rounded to the correct decimal)

5 0
3 years ago
Why do people want different kinds of light bulbs?
ololo11 [35]

Answer:

LED bulbs fit standard light sockets and are the most energy-efficient option. LEDs have lower wattage than incandescent bulbs but emit the same light output. This allows them to produce the same amount of light but use less energy. LEDs can last over 20 years and don't contain mercury

7 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
Measure the initial temperature of the water to the
LuckyWell [14K]

Answer:

Answer:

100

22.4

27.1

Explanation:

Explanation:

just did it on edge .

Hope this helps

8 0
3 years ago
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