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3 years ago

what is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.250M HBr solution

Chemistry

1 answer:

EastWind [94]3 years ago

7 0

The molarity of a CsOH solution with 30mL would be .284M

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What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.

zloy xaker [14]

For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be :

Br2 + S2032- + 5H20 -- > BR2- + 2S02- + H+

Hope this helps

8 0

3 years ago

If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temp

emmasim [6.3K]

<span>C6H12 = 6x12 + 6x1 = 78.
The equation indicates that 2x78 = 156g benzene will produce 6542kJ.
Using proportions you can then calculate that
x/6542kJ = 7.9g / 156g
x = 331.3kJ = 331300J.

heat = mass x ΔT x 4.18J/g°
ΔT = 331300J / (5691g x 4.18J/g°) = 13.9°

final temp = 21 + 14° = 35°C</span>

4 0

3 years ago

Describe the overall enthalpy of the chemical reactants compared to the enthalpy of the chemical products in the combustion of p

Veronika [31]

Answer:

A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:

C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol

The value given for ΔH∘rxnΔHrxn∘ means that:

a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.

b. the reaction is endothermic.

c. the enthalpy of formation of propane is 2202 kJ/mol.

d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.

e. None of these.

3 0

1 year ago

How do multiple bonds affect the shape of a molecule?.

jok3333 [9.3K]

Answer:

hyprogenic

Explanation:

hope it's help

make me brainless tyy

8 0

2 years ago

What is the mass of 2.16 moles of sulfur dioxide (SO2)?

Luda [366]

<h3>Answer:</h3>

138 g SO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 2.16 moles SO₂

[Solve] grams (mass) SO₂

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 2.16 \ mol \ SO_2(\frac{64.07 \ g \ SO_2}{1 \ mol \ SO_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 138.391 \ g \ SO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

138.391 g SO₂ ≈ 138 g SO₂

6 0

2 years ago