Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
</span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg.
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605
mass water = 920 mL x 1 g/mL = 920 g
moles water = 920 g/ 18.02 g/mol=51.1
mole fraction water = 51.1 / 51.1 + 0.605 =0.988
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
Answer: The sodium peroxide needed per sailor in a 24 hr period is 674 grams.
Explanation:
According to ideal gas equation:
P = pressure of gas = 1.02 atm
V = Volume of gas = 150.0 ml = 0.15 L
n = number of moles of carbon dioxide = ?
R = gas constant =
T =temperature =

According to stoichiometry:
2 moles of carbon dioxide require = 2 moles of sodium peroxide
Thus 0.006 moles carbon dioxide require=
moles of sodium peroxide
Mass of sodium peroxide needed for 24 hour=
Thus sodium peroxide needed per sailor in a 24 hr period is 674 grams.
The answers would be
1.b
2.c
3.a
Molar mass F₂O₃ = 159.69 g/mol
1 mole ------------------ 159.69 g
0.7891 moles ---------- ? g
mass = 0.7891 x 159.69 / 1
= 126.01 g
hope this helps!