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OLga [1]
3 years ago
8

Which of the following is not an example of an engine?

Physics
1 answer:
SashulF [63]3 years ago
4 0
The answer is A. waterfall
To be considered as an engine , it should be a Man-made objects that could be used to produce power that creates motions.
From all the options above could be used to produce such power, but the waterfall is not made by mandkind
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Which of the following statements apply to electric charges?
Gre4nikov [31]

Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

6 0
3 years ago
Is 5m.what<br>In si system, the length of a body is<br>does it mean?​
lozanna [386]

Answer: Some conversions from one system of units to another need to be exact, without increasing or decreasing the precision of the first measurement. This is sometimes called soft conversion. It does not involve changing the physical configuration of the item being measured.

Explanation:

4 0
3 years ago
Which of the following would be the best thermal conductor?
Elis [28]
The best thermal conductor is b. metal
4 0
3 years ago
Read 2 more answers
It is determined that a certain wave of infrared light has a wavelength of 8.45 mm. Given that c=2.99 ×108 m/s, what is the freq
irina [24]

Answer:

The frequency of infrared wave is 35.385 GHz

Explanation:

Given data:

Wavelength of infrared light = 8.45 mm = 8.45 x 10^{-3} m

Velocity of infrared light = 2.99 x 10^{8} m/s

To find: frequency of the infrared wave = ?

We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:

c = μλ, where

c is velocity of light

μ is frequency of light

λ is wavelength of light

Hence the frequency of light  μ = c/λ

                                                     = \frac{2.99 x 10^{8} m/s }{8.45 x 10^{-3}m }

                                                     = \frac{299}{8.45} x 10^{9} s^{-1}

                                                     =  35.385  x  10^{9} Hz   (since 1 s^{-1} = 1 Hz)

                                                     = 35.385 GHz

6 0
4 years ago
Read 2 more answers
A planet of mass m moves around the Sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from th
zzz [600]

Answer:

the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

Explanation:

Given the data i  the question;

mass of sun = M

minimum and maximum distance = r1 and r2 respectively

Now, using Kepler's third law,

" the square of period T of any planet is proportional to the cube of average distance "

T² ∝ R³

average distance a = ( r1 + r2 ) / 2

we know that

T² = 4π²a³ / GM

T² = 4π² [( ( r1 + r2 ) / 2 )³ / GM ]

T² = 4π² [( ( r1 + r2 )³ / 8 ) / GM ]

T² = 4π² [( r1 + r2 )³ / 8GM ]

T = √[ 4π² [( r1 + r2 )³ / 8GM ] ]

T = 2π √[( r1 + r2 )³ / 8GM ]

Therefore, the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

5 0
3 years ago
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