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Artyom0805 [142]
4 years ago
9

Calculate the quantity of heat absorbed by 50 g of water that warms from 30∘C to 90∘C.

Physics
1 answer:
natima [27]4 years ago
5 0

Answer:

12,558 J

Explanation:

The amount of heat absorbed by the water is given by:

Q=mC_S \Delta T

where

m = 50 g is the mass of the water

C_s = 4.186 J/gC is the water specific heat

\Delta T=90C-30C=60^{\circ}C is the temperature increase of the water

Substituting into the formula, we find

Q=(50.0 g)(4.186 J/gC)(60^{\circ}C)=12,558 J

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