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FrozenT [24]
3 years ago
15

A 1200 kg car collides with a 160 kg deer (don't worry, the deer survives and goes on to cause several more car crashes). The co

llision results in an acceleration ("deceleration") of 2.5 m/(sec)^2 for the car. Find the acceleration of the deer during the collision.
Physics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

18.75

Explanation:

p=mv, where p is momentum, m is mass, and v is velocity. For the car:

p=1200*2.5=3000

For the deer:

3000=160*v

v=18.75m/s

Hope this helps!

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A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei
Alenkinab [10]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

F = (150\ N)Sin\ 20^o

<u>F = 51.3°</u>

8 0
3 years ago
Two horizontal rods are each held up by vertical strings tied to their ends. Rod 1 has length L and mass M; rod 2 has length 2L
antiseptic1488 [7]

Answer:

Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.

Explanation:

For the rod 1 the angular acceleration is

\tau_1 = I_1\alpha _1 \\\\\alpha_1 = \dfrac{\tau_1}{I_1}

Similarly, for rod 2

\alpha_2 = \dfrac{\tau_2}{I_2}.

Now, the moment of inertia for rod 1 is

I_1 = \dfrac{1}{3}ML^2,

and the torque acting on it is (about the center of mass)

\tau_1 = Mg\dfrac{L}{2};

therefore, the angular acceleration of rod 1 is  

\alpha_1 = \dfrac{Mg\dfrac{L}{2}}{\dfrac{1}{3}ML^2},

\boxed{\alpha_1 = \dfrac{3g}{2L} }

Now, for rod 2 the moment of inertia is

I_2 = \dfrac{1}{3}(2M)(2L)^2

I_2 = \dfrac{8}{3} ML^2,

and the torque acting is (about the center of mass)

\tau _2 = (2M)g \dfrac{(2L)}{2}

\tau _2 = 2MgL;

therefore, the angular acceleration \alpha_2 is

\alpha_2 = \dfrac{2MgL;}{\dfrac{8}{3} ML^2,}.

\boxed{\alpha_2 = \dfrac{3g}{4L}}

We see here that

\dfrac{3g}{2L} > \dfrac{3g}{4L}

therefore

\boxed{\alpha_1 > \alpha_2.}

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.

7 0
3 years ago
The Rite of Spring was composed by
7nadin3 [17]

The 'Rite of Spring' was composed by Igor Stravinsky.

7 0
4 years ago
Which one of these is not a rock? A. granite B. Shale C. marble D. Diamond
saul85 [17]

DIAMONDS are NOT rocks. Diamonds are minerals, rocks are made up of many different fragments of minerals.

3 0
4 years ago
You extend an impromptu invitation to a friend for dinner. The only food you have is a couple of frozen steaks. You wish to defr
kakasveta [241]

Answer:

Microwave: Radiation

Water: Conduction, convection & radiation.

Explanation:

  • When we heat a food using microwave then the water content of the food is only heated by the microwave.
  • Microwaves make the molecules of water vibrate frequently with a frequency closer to the frequency of microwaves and this increases the kinetic energy of the molecules which produces heat in the water molecules this heat then propagates to the whole food by conduction and convection, but the heat enters the food only via radiation.

Now when the food item is kept into warm water then the molecules closer to the food heat the food by conduction through direct energy transfer by lattice vibrations and when they become cooler than the mass of water all around then due to density difference they settle down and their place is occupied by warmer molecules around in the fluid leading to convection.

Radiation of energy from a mass occurs continuously irrespective of the medium present there. So the heat of water also enters the food by radiation of energy from the water molecules.

3 0
3 years ago
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