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FrozenT [24]
3 years ago
15

A 1200 kg car collides with a 160 kg deer (don't worry, the deer survives and goes on to cause several more car crashes). The co

llision results in an acceleration ("deceleration") of 2.5 m/(sec)^2 for the car. Find the acceleration of the deer during the collision.
Physics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

18.75

Explanation:

p=mv, where p is momentum, m is mass, and v is velocity. For the car:

p=1200*2.5=3000

For the deer:

3000=160*v

v=18.75m/s

Hope this helps!

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The electric motor of a model train accelerates the train from rest to 0.540 m/s in 27.0 ms. The total mass of the train is 610
Gnesinka [82]

Answer:

The value  is  P  =3.294 \  W

Explanation:

From the question we are that

     The velocity  v  =  0.540  \  m/s

      The  time taken is  t =  27.0 ms  = 27.0 *10^{-3} \ s

     The  total mass of the train is  m  =  610 \ g  =  0.610 \ kg

Generally the average power delivered is mathematically represented as

     P  =\frac{KE }{t}    

     P  =\frac{  \frac{1}{2}  *  m  *  v^2 }{t}    

=>  P  =\frac{  \frac{1}{2}  *  0.610   *   0.540 ^2 }{ 27.0 *10^{-3}}    

=>  P  =3.294 \  W  

5 0
3 years ago
Read 2 more answers
Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its
antoniya [11.8K]

A) Moment of inertia about an axis passing through the point where the two segments meet : $I_A=\frac{1}{12} M L^2$

B) Moment of inertia passing through the point where the midpoint of the line connects to its two ends: $I x=\frac{1}{3} M L^2$

What is Moment of inertia?

The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.

A) The moment of inertia about an axis passing through the point where the two segments meet is $I_A=\frac{1}{12} M L^2$given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.

B) Determine the moment of inertia about an axis passing through the point midpoint of the line which connects the two ends

First step: determine the distance between the ends ( d )

After applying Pythagoras theorem$\mathrm{d}=\frac{\sqrt{2}}{2} L$

Next step : determine distance between the two axis $(\mathrm{x})$

After applying Pythagoras theorem

\mathrm{x}=\frac{\sqrt{2}}{4} L$$

Final step : Calculate the value of $\mathrm{I}_{\mathrm{x}}$

applying Parallel Axis Theorem

$$I_x=I_8+M x^2$$

$$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$$

Hence we can conclude that Moment of inertia about an axis passing through the point where the two segments meet: $I_A=\frac{1}{12} M L^2$, Moment of inertia passing through the point where the midpoint of the line connects its two ends: $I x=\frac{1}{3} M L^2$

To learn more about moment of inertia visit:brainly.com/question/15246709

#SPJ4

5 0
1 year ago
A car slows down from speed of 72
Nastasia [14]

Explanation:

Given parameters:

Initial velocity = 72km/hr

Final velocity  = 0km/hr

Time taken  = 25s

Unknown:

Acceleration = ?

Solution:

To solve this problem, convert km/hr to m/s;

           1000m = 1km

           3600s = 1hr

  72km/hr;

          1km/hr  = 0.278m/s

         72km/hr = 0.278 x 72  = 20.02m/s

Acceleration is the change in velocity divided by the time taken;

       Acceleration = \frac{final velocity - initial velocity }{time}  

       Acceleration  = \frac{0 - 20.02}{25}   = -0.8m/s

The car  is actually decelerating at a rate of 0.8m/s

5 0
2 years ago
Jupiter is made of gas(like Saturn, Uranus and Neptune). What would happen to the strength of gravity if you
garik1379 [7]

Answer:

a) The strength of gravity decreases if one moved away from Jupiter

b) The strength of gravity increases if one fell into Jupiter

Explanation:

The gravitational attraction is given by Newton law of gravitation as follows;

Force \ (strength) \ of \ gravity = \dfrac{G \times M \times m}{R^2}

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)

M = The mass of Jupiter

m = The mass of the nearby body

R = The distance between the centers of Jupiter and the body

From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies

Therefore, as one moves away, R increases, and the strength of gravity reduces

Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.

7 0
2 years ago
A parachutist of mass 100 kg falls from a height of 500 m. Under realistic conditions, she experiences air resistance. Based on
antoniya [11.8K]
Given:
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²

velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s

KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J

Pls. see attachment. 

  

5 0
3 years ago
Read 2 more answers
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