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FrozenT [24]
3 years ago
15

A 1200 kg car collides with a 160 kg deer (don't worry, the deer survives and goes on to cause several more car crashes). The co

llision results in an acceleration ("deceleration") of 2.5 m/(sec)^2 for the car. Find the acceleration of the deer during the collision.
Physics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

18.75

Explanation:

p=mv, where p is momentum, m is mass, and v is velocity. For the car:

p=1200*2.5=3000

For the deer:

3000=160*v

v=18.75m/s

Hope this helps!

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Can u read a ruler it's very hard
iris [78.8K]

Answer:

A. 1 inch

B. 1/2 inch

C. 3/4 inch

D. 1/8 inch

E. 1 7/8 inch

F. 1 1/2 inch

G. 3 1/15 inch

H. 2 5/8 inch

I. 2 1/4 inch

8 0
3 years ago
If the activity of a radionuclide decreases from 5,000 disintegrations per minute to 625 disintegrations per minute
lys-0071 [83]

Answer:

4 hrs

Explanation:

625 = 5000 (1/2)^n

625/5000 = 1/2^n

n = 3 half lives

3 half lives = 12 hours       1 half life = 4 hrs

7 0
3 years ago
A element source has a decayed constant of 13.6pico per second. Calculate the half life of this element. ​
vladimir1956 [14]

Answer:

5.1 x 10¹⁰s

Explanation:

Given parameters:

Decay constant  = 13.6 x 10⁻¹²/s

Unknown:

Half life of the element  = ?

Solution:

From the decay constant, we can find the half-life of this radioactive element.

  Half-life  = \frac{0.693}{decay constant}  

     Half-life  = \frac{0.693}{13.6 x 10^{-12} }   = 5.1 x 10¹⁰s

4 0
3 years ago
1. It’s fall and time for the corn maze and bonfire and you just can’t wait. On your way to the farm though a turkey flies out i
Reptile [31]

Acceleration = (change in velocity ( final speed - starting speed))/ (time)

Acceleration = (18-30)/10.5

Acceleration = -12/10.5

Acceleration = -1.14 m/s^2

Distance = 30m/s x 10.5s + 1/2(1.14)(10.5)^2

Distance = 252.2 meters

8 0
3 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
4 years ago
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