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kompoz [17]
3 years ago
9

. The spot on Jupiter is a _______? Volcano Ocean Storm Unknown

Physics
1 answer:
MaRussiya [10]3 years ago
8 0
Storm!! Hope I could help
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When is an object that has been dropped from a great height through the air closest to vein in a free fall?
Elza [17]
-- "Free fall" means no forces acting on the object except for gravity.

-- An object dropped through air has two forces on it -- gravity and air resistance.

-- So we're looking for the part of the drop where air resistance is smallest.

-- The force of air resistance depends on the speed through the air, so the
force of air resistance is smallest when <em>velocity downward is smallest</em>.



7 0
3 years ago
Read 2 more answers
Add to
TEA [102]

Answer:

1) x_total = 2.7 km=2700 m, 2)   t_total = 1926 s,  3)   v_avg = 1.40 m / s

Explanation:

1) To solve this uniform velocity problem, we must find the displacement of each part and add them.

        x_total = x₁ + x₂

        x_total = 0.7 + 2.0

        x_total = 2.7 km

2) how long does it take for this tour

         

truck

        v = x₁ / t₁

        t₁ = x₁ / v

        t₁ = 0.7 / 20

        t₁ = 0.035 h

Let's reduce the time to the SI system

         t₁ = 0.035 h (3600 s / 1h) = 126 s

when he is walking

         t₂ = 30 min (60 s / 1min) = 1800 s

the total time is

        t_total = t₁ + t₂

        t_total = 126 + 1800

        t_total = 1926 s

3) the average velocity is defined as the displacement in the inerval between time

        v_avg = x_total / t_total

         v_avg = 2700/1926

         v_avg = 1.40 m / s

8 0
3 years ago
A 750 g air-track glider attached to a spring with spring constant 14.0 N/m is sitting at rest on a frictionless air track. A 20
alexandr402 [8]

Answer:

the amplitude of  the subsequent oscillations is 0.11  m

the period of the subsequent oscillations is 1.94 s

Explanation:

given Information:

the mass of air-track glider, m_{1} = 750 g = 0.75 kg

spring constant, k = 13.0 N/m

the mass of glider, m_{2} = 200 g = 0.2 kg

the speed of glider,  v_{2} = 170 cm/s = 1.7 m/s

the amplitude of  the subsequent oscillations is A = 0.11  m

according to mechanical enery equation, we have

A = \sqrt{\frac{m_{1} +m_{2} }{k} }v_{f}

where

A is the amplitude and  v_{f} is the final speed.

to find v_{f}, we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.

P_{f} = P_{i}

(m_{1} +m_{2} )v_{f} = m_{1} v_{1} +m_{2}v_{2}

v_{1} = 0, thus

(0.75+0.2)v_{f} = (0.75)(0)+(0.2)(1.7)

0.95 v_{f} = 0.34

v_{f} = 0.36 m/s

Now we can calculate the amplitude

A = \sqrt{\frac{0.75 +0.2 }{10} }0.36

A = 0.11  m

the period of the subsequent oscillations is T = 1.94 s

the equation for period is

T = 2π\sqrt{\frac{m_{1}+m_{2}  }{k} }

T = 2π\sqrt{\frac{0.75+0.2  }{10} }

T = 1.94 s

7 0
3 years ago
Consider light energy that is momentarily absorbed in glass and then re-emitted. Compared to the absorbed light, the frequency o
fredd [130]

The frequency of the re-emitted light is identical to that of the absorbed light.

To find the answer, we need to know more about the frequency of light.

<h3> Why the re-emitted light has the same frequency?</h3>
  • The wavelength of the light that is momentarily absorbed in glass and then re-emitted is the same, which explains why the re-emitted light has the same frequency as the absorbed light and the frequency of the absorbed light is the same.
  • An electromagnetic wave's energy is inversely related to its frequency.
  • The relationship between the wave's wavelength and frequency depends on the speed of light:

                              frequency=\frac{c}{wave length} , c is the speed of light.

  • Despite not having mass, light still has energy, and that energy is conserved.
  • As a result, in order for there to be energy conservation, the energy of the light that is received and reemitted must be equal.

Thus, we can conclude that, the re-emitted light's frequency matches the absorbed light's frequency.

Learn more about frequency here:

brainly.com/question/26754018

#SPJ4

4 0
1 year ago
6) If Bam was hit by the hand with a force of 1200N. If he has a mass of 81kg, what acceleration did
bazaltina [42]

Answer:

14.81 m/s^2

Explanation:

f=m×a

1200=81×a

a=1200/81

a=14.81

3 0
3 years ago
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