C2H6O + O2 ---> C2H4O2 + H2O

using the molar masses:-
24+ 6 + 16 g of C2H6O produces 24 + 4 + 32 g C2H4O2 (theoretical)
46 g produces 60g

60 g C2H4O2 is produced from 46g C2H6O
1g . .................................46/60 g
700g ................................. (46/60) * 700 Theoretically

But as the yield is only 7.5%

the required amount is ((46/60) * 700 ) / 0.075 = 7155.56 g

= 7.156 kg to nearest gram. Answer

8 0

3 years ago

Evaluate (714 mm )/(37 s ) to three significant figures and express answer in si units using an appropriate prefix.

romanna [79]

The SI base units for length is meter (m) and for time is seconds (s).

The given ratio is $\frac{714 mm}{37 s}$

$\frac{714 mm}{37 s} = 19.297 mm/s \simeq 19.3 mm/s$

Converting mm/s to m/s as:

Since, 1 mm/s = 0.001 m/s

So, $19.3 mm/s = 0.0193 m/s$

Since, zeroes to the left side of the non-zero number are not significant hence, the evaluation of $\frac{714 mm}{37 s}$ to three significant figures and answer in SI units is $0.0193 m/s$ .

5 0

3 years ago

T-Butyl alcohol was produced by the liquid-phase hydration (using water, W) of isobutene (I) over an Amberlyst-15 catalyst.

Minchanka [31]

Answer:

True

Explanation:

This is because, The hydroboration oxidation of an alkene which is isobutene in the presence of a catalyst will result to alcohol as the product . Therefore, the OH group will attach or link itself to the carbon which is less obstructed. Thus this reaction is in accordance to Anti-Markownikoff's rule.

So isobutene on hydroboration oxidation will produce ter isobutyl alcohol.

8 0

3 years ago