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3 years ago

At standard temperature, a gas has a volume of 275 mL. The temperature is then increased to

Chemistry

1 answer:

ratelena [41]3 years ago

5 0

Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

$\frac{v1}{t1} = \frac{v2}{t2}$

temperature is measured in degrees Kelvin.

And

$v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?$

?mL

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What are the units of k in the following rate law?

Ludmilka [50]

Answer:

B. $\frac{1}{M^{2} s }$

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * $M^{2}$ * $M^{1}$

k= (M/s) / ( $M^{3}$ )

k= $\frac{1}{M^{2} s }$

You can also use this predetermined formula to solve this problem faster: k= $\frac{M^{1-n} }{s }$

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= $\frac{M^{1-n} }{s }$

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3 years ago

What is chromatography?

denpristay [2]

Its c.chromatography is the process of separating solutions on the basis of their boiling points

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3 years ago

Why do molecules of oxygen have to have an even number of atoms?

Ann [662]

Answer:this is all i found out

Oxygen is known as a diatomic molecule. Oxygen atom has atomic number as 8 so it has its K shell completely filled with 2 electrons. While it has only 6 electrons in L shell which requires 8 electrons to get inert gas configuration. So oxygen atom shares 2 electrons with another oxygen atom to form a diatomic molecule.

Explanation:

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3 years ago

How many molecules of manganese (IV) sulfate are there if you are given 542.32g?

MAVERICK [17]

Answer:

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2 years ago

The reaction of 4.8g of sulfur and 5.4g aluminum yields 4.5g Al2S3. 3S+2AL-->Al2S3 Determine the percent yield of Al2S3.

Goshia [24]

Answer:

59.9% is the percent yield for the 4.5 g of produced Al₂S₃

Explanation:

Let's determine the reaction:

3S + 2Al → Al₂S₃

First of all, let's determine the limiting reactant. We need to convert the mass to moles:

4.8 g /32.06g/mol = 0.150 moles of S

5.4 g / 26.98 g/mol = 0.200 moles of Al

3 moles of S react to 2 moles of Al

Then, 0.150 moles of S may react to (0.150 . 2)/3 = 0.1 ,moles of Al

We have 0.200 moles and we only have 0.1. As we have excess of Al, this is the excess reactant. In conclussion, the limiting reagent is S.

2 moles of Al react to 3 moles of S

Then 0.2 moles of Al may react to (0.2 . 3) /2 = 0.3 moles of S. (We only have 0.150 moles)

Let's go to the product, 3 moles of S can produce 1 mol of Al₂S₃

Then 0.150 moles of S, may produce (0.150 . 1) /3 = 0.05 moles.

We convert moles to mass to determine the thoretical yield:

0.05 mol . 150.15g /mol = 7.50g

Percent yield = (Produced yield/Theoretical yield) . 100

% = (4.5g / 7.5g) . 100 = 59.9%

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2 years ago