Question

At standard temperature, a gas has a volume of 275 mL. The temperature is then increased to

Answer 1

Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

$\frac{v1}{t1} = \frac{v2}{t2}$

temperature is measured in degrees Kelvin.

And

$v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?$

?mL