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Tju [1.3M]
4 years ago
11

Assume human blood is iso-osmotic or isotonic with a 0.16 mol/lit saline (NaCl) solution (the solution does not change the volum

e of the blood cell) and for simplicity all dissolved salts in the solution are NaCl rather than ions. Estimate osmotic pressure at 37°C.
Chemistry
1 answer:
const2013 [10]4 years ago
8 0

Answer:

π = 4.1 atm

Explanation:

We can calculate the osmotic pressure exerted by a solution using the following expression.

π = M . R . T

where,

π is the osmotic pressure

M is the molar concentration of the solution

R is the ideal gas constant

T is the absolute temperature

The absolute temperature is 37 + 273 = 310 K

π = M . R . T

π = (0.16 mol/L) . (0.082atm.L/mol.K) . 310 K = 4.1 atm

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If K > 1 , reaction is proceeding from left to right .

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C₉H₇NH⁺ is giving H⁺ so it is a bronsted acid and NO₂⁻ is accepting H⁺ so it is a bronsted base .

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A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and<br> 32 C.
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1255.4L

Explanation:

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T₂  = 32°C

Unknown:

V₂  = ?

Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

 take the units to the appropriate ones;

             kpa to atm,  °C to K

P₂ = 319kpa in atm gives 3.15atm

P₁  = 928kpa gives 9.16atm

T₂  = 32°C gives 273 + 32  = 305K

T₁  = 129°C gives 129 + 273  = 402K

Input the values in the equation and solve for V₂;

        \frac{9.16  x 569}{402}   = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

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