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3 years ago

Please help with the attached picture question 21, 22, 23

Chemistry

1 answer:

klasskru [66]3 years ago

5 0

Explanation:

21. The given molecule for cracking is tetradecane.

On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.

The chemical equation is shown below:

$C_1_4H_3_0->C_1_0H_2_2+2C_2H_4$

22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.

Thus among the given options, the first option is the correct one.

23. Isomers of butanol are shown below:

It is 2-butanol.

The position of -OH group changes to the second carbon.

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If 3.0 g of NH3 reacts with 5.0 g of HCl, what is the limiting reactant?

ELEN [110]

<h2>Answer:HCl</h2>

Explanation:

$\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}$

For $NH_{3},$

$\text{given mass}=3g$

$\text{molar mass}=14+3=17g$

$n_{NH_{3}}=\frac{3}{17}=0.176$

For $HCl,$

$\text{given mass}=5g$

$\text{molar mass}=1+35.5=36.5g$

$n_{HCl}=\frac{5}{36.5}=0.136$

The reaction between $NH_{3}$ and $HCl$ is

$NH_{3}+HCl$ → $NH_{4}Cl$

So,one mole of $NH_{3}$ requires one mole of $HCl$

$0.176$ moles of $NH_{3}$ requires $0.176$ moles of $HCl$

But there are only $0.136$ moles of $HCl$ available.

$HCl$ will be consumed first.

So, $HCl$ is the limiting reagent.

7 0

3 years ago

For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of

Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O; Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

7 0

3 years ago

Read 2 more answers

The ____ is the time required for one half of the atoms of a radio scope to ____.

mash [69]

First blank is: Half-Life
Second Blank is: decay into its products

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3 years ago

Which of the following represents positron emission? Select one: a. 3015P ---> 3014Si + ___ b. 23892U ---> 23490Th + ___ c

xxTIMURxx [149]

The simple trick which one can consider in such problem where it is asked for positron emission is :
<span>When the atomic number goes DOWN by one and mass number remains unchanged, then a positron is emitted.
</span>
<span>a. </span> $P^{30}_{15} ----\ \textgreater \ Si^{30}_{14} + e^{0}_{1}^+$
<span>
Here the atomic number decreases by one.

Similarly, options b and d are eliminated.

Option c is also not the answer.
For c, Count the atomic number on left side and compare it with right side. You will see it is 9 on left and 8 on right. Atomic no. did go down by 1. But the atomic mass is changed as well.

</span>

8 0

3 years ago

A reaction was suppose to produce 20 L of gas. Only 12 litters of gas were produced in the lab. What is the percent yield for th

pogonyaev

Answer:

$\boxed {\boxed {\sf 60 \%}}$