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dolphi86 [110]
3 years ago
11

Which law represents a balanced chemical equation?

Physics
2 answers:
neonofarm [45]3 years ago
6 0
Law of conservation of mass
mylen [45]3 years ago
3 0

Yea the answer is C.law of conservation of mass.

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A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of th
mojhsa [17]

Answer: The angle of inclination is nearly 30°

Explanation:

For a body on an inclined plane, the coefficient of friction between the body and the plane is equal to the ratio of the moving force applied to the body to the frictional force acting on the body.

If uK coefficient of friction;

Fm is the moving force

R is the normal reaction on the body

Mathematically uK = Fm/R

Fm = WSin(theta)

R = Wcos(theta)

uK = Wsin(theta)/Wcos(theta)

uK = tan(theta)

theta = arctan(uK)

If uK is 0.58

theta = arctan0.58

theta = 30°

The angle of the inclined will be 30°

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3 years ago
The (blank) of vibration of a wave is defined as that which has the lowest frequency
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Fundamental frequency
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1. Starting today. I will now change my behavior/s like ______________ because _________________
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Answer:

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it's just my own understanding

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the weight of a body is more at polar regions of the earth than that at the equatorial regions? why give reason​
ella [17]

Answer:

The weight of an object at the Earth's South Pole is slightly more than its weight at the Equator because the polar radius of the Earth is slightly less than the equatorial radius. Though the mass of an object remains constant, its weight varies according to its location.

Explanation:

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3 years ago
Three identical metallic conducting spheres carry the following charges: q = +3.8 μC, q = −2.6 μC, and q = −8.8 μC. The spheres
Kitty [74]

Answer:

-4.1μC is the final charge on the third sphere

Explanation:

From the given data, q1 and q2 are brought into contact as they are both conductors,  as such there will be evenly distribution of charges.

a) charge on each sphere(Q) = q1 + q2 / 2

= +3.8 μC + (- 2.6 μC) / 2 = 1.2μC/2 = 0.6μC

b) Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with q3 = Q + q3 / 2

= 0.6μC - 8.8 μC /2 = -8.2 μC/2

= -4.1μC is the final charge on the third sphere.

6 0
3 years ago
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