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dolphi86 [110]
3 years ago
11

Which law represents a balanced chemical equation?

Physics
2 answers:
neonofarm [45]3 years ago
6 0
Law of conservation of mass
mylen [45]3 years ago
3 0

Yea the answer is C.law of conservation of mass.

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A cylinder with moment of inertia I1 rotates with angular speed ω0 about a frictionless vertical axle. A second cylinder, with m
MAXImum [283]

Answer:

Part(a): The final angular velocity is \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b): The ratio of the rotational energies is \dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})},showing the the energy of th system will decrease.

Explanation:

Part(a):

If 'I' be the moment of inertia of an object and '\omega' be its angular velocity then the angular momentum 'L' of the object can  be written as

L = I \omega

If 'I_{1}' and 'I_{2}' be the moment of inertia of the two cylinders and '\omega_{1}' and '\omega_{2}' be the initial angular velocity of the cylinders and '\omega_{1}{'}' and '\omega_{2}^'}' be their respective final angular velocity, then from conservation of angular momentum,

I_{1} \omega_{1} + I_{2} \omega_{2} = I_{1} \omega_{1}^{'} + I_{2} \omega_{2}^{'}

Given, \omega_{1} = \omega_{i},~\omega_{2} = 0,~\omega_{1}^{'} = \omega_{2}^{'} = \omega_{f}. From the above expression

&& I_{1} \omega_{i} = (I_{1} + I_{2}) \omega_{f}\\&or,& \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b):

Initial kinetic energy  

K_{i} = \dfrac{1}{2} I_{1} \omega_{i}^{2}

and Final kinetic energy

K_{f} = \dfrac{1}{2}(I_{1} + I_{2}) \omega_{f}^{2}

Substituting the value of \omega_{f},

&& K_{f} = \dfrac{1}{2}(I_{1} + I_{2})\dfrac{I_{1}^{2}\omega_{i}^{2}}{(I_{1} + I_{2})^{2}} = \dfrac{1}{(I_{1} + I_{2})} \dfrac{1}{2}I_{1}\omega_{i}^{2} = \dfrac{1}{(I_{1} + I_{2})} K_{i}\\&\dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})}

The above expression shows that the ebergy of the system will decrease.

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3 years ago
Describing the motion of an object
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Answer:

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- Sophia

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Answer:

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Hope This Helps

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2 years ago
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