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suter [353]
3 years ago
8

Science homework help

Physics
1 answer:
matrenka [14]3 years ago
7 0
1. electrons
2. positive to negative
3. insulator
4. TRUE
5. closed circuit
6. TRUE
7. series
8. TRUE
9. v=ir
10. TRUE

Hope this helps! :)
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3.A golf ball is hit of it’s tee, 200m down the fairway.
Alinara [238K]

<u>Answers:</u>


3. The diagrams showing the forces acting on the golf ball are in the figure attached. Let’s have a detailed look:


a) Here the ball is under 2 forces:


F1 which is called The Normal force and is perpendicular to the surface of the tee where the ball rests


-F1, related to the gravity force, to the weight of the ball, and has the same magnitude, but the opposite direction (That’s why it has a negative sign).



In this case the sum of the forces is 0



b) Here we have again forces F1 and –F1, but in this very moment the club strikes the ball and we have:


F2, the force of the strike





c) While the ball is in its flight, it is under the following forces:


F1, the force of the lift through the air


-F2, the gravity force

-F3, the force of air resistance, also called drag


F4, the tangencial force of the ball flight




4. Here are the sizes and directions of the resultant forces:


i)Two forces of the same magnitude or size are applied to this block, but in opposite directions (in the x-axis). This is expressed as:



F=-10N+10N=0 The resulting force is zero



ii) Two forces of different size and opposite directions in the y-axis are applied to this block. The sum of the forces is:



F=30N-40N=-10N This means the resulting force is 10N applied downwards



iii) In this case the only force applied to the block is -5N applied downwards



iv) Here there are four forces applied to the block.  

In the y-axis we have to forces of the same size but opposite directions:



F1=10N-10N=0 This means the applied force in the y-axis is zero



In the x-axis we have two forces of different size and opposite directions:



F2=-15N+10N=-5N This means the resulting force is applied to the –x-side



4 0
3 years ago
Suppose that the sun shrank in size but that its mass remained the same. What would happen to the orbit of the earth?
Minchanka [31]

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

G\frac{Mm}{r^2} = m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

r=\frac{GM}{v^2}

Also,

v=\omega r

where \omega is the angular velocity of the Earth's orbit. So we can rewrite the equation as

r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

6 0
3 years ago
Describe how you can determine:<br>a) Volume of an irregular body<br>b) Density of a liquid​
vlada-n [284]

Density of liquid try thank you so much

7 0
3 years ago
Read 2 more answers
Suppose you are standing on the center of a merry-go-round that is at rest. You are holding a spinning bicycle wheel over your h
ioda

Answer:

B. It begins to rotate counterclockwise

Explanation:

It can happen that the merry-go-round remains at rest in the case when the person is standing on the axle  of the merry go round whose axis is fixed to some rigid support, but here the person is standing at the center of the merry-go-round not at the axle hence the according to the conservation of angular momentum. Angular momentum is given as:

L=I.\omega

for the conservation of momentum

I.\omega=I'.\omega'

where:

I= moment of inertia of the merry-go-round

\omega= angular velocity of the merry-go-round

I'= moment of inertia of the bicycle wheel

\omega'= angular velocity of the wheel

As the person tries to stop the wheel which is rotating then the person feels an opposing force which tries to moves the whole system in its direction.

6 0
3 years ago
Two children of mass 18 kg and 29 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c
DedPeter [7]

Answer:

3.085 [m].

Explanation:

1) The rule:

m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;

2) according to the condigion l₁+l₂=5, then

3) it is possible to make up the system:

\left \{ {{l_1+l_2=5} \atop {m_1*l_1=m_2*l_2}} \right. \ = > \ \left \{ {{l_1=5-l_2} \atop {18*(5-l_2)=29*l_2}} \right. \ = > \ \left \{ {{l_1=\frac{145}{47}} \atop {l_2=\frac{90}{47}}} \right.

4) finally, l₁=145/47≈3.085 [m].

7 0
2 years ago
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