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Tcecarenko [31]
2 years ago
5

During an Olympic bobsled run, the Jamaican team makes a turn of radius 8.80 m at a speed of 105 km/h. What is the ratio of thei

r acceleration to g
Physics
1 answer:
malfutka [58]2 years ago
7 0

Answer:

Explanation:

105 km/hr = 29.17 m/s

r = (v²/R) / g

r = (29.17²/8.80) / 9.81

r = 9.85

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Answer:

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N

Thus, the net force over the body is:

F=(913.14N)\hat{i}+(274.87N)\hat{j}

Next, you calculate the magnitude of the force:

F=\sqrt{(913.14N)+(274.87N)^2}=953.61N

and the direction is:

\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°

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Explanation:

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3 0
1 year ago
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2 years ago
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