4.1 x to the 10th To the power -3
Answer:
Explanation:
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In this case we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:
Whereas we solve for as the required final pressure:
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The balanced chemical equation for reaction of and is as follows:
From the balanced chemical equation, 2 mol of reacts with 1 mol of .
First calculating number of moles of as follows:
On rearranging,
Here, M is molarity and V is volume. The molarity of is given 0.274 M or mol/L and volume 155 mL, putting the values,
Since, 1 mol of reacts with 2 mol of thus, number of moles of will be .
Now, molarity of is given 0.305 M or mol/L thus, volume can be calculated as follows:
Therefore, volume of is 278.5 mL.
Some properties to differentiate between the minerals include:
Ductility
Malleability
Luster
Particle Size
Ability to react with chemicals
etc....
Answer:
0.31 mole
Explanation:
The following data were obtained from the question:
Mass of SF6 = 45.0 g
Number of mole of SF6 =..?
Next, we shall determine the molar mass of SF6.
This can be obtained as follow:
Molar mass of SF6 = 32 + (19×6)
Molar mass of SF6 = 32 + 114
Molar mass of SF6 = 146 g/mol
Finally, we shall determine the number of mole in 45 g of SF6 as follow:
Molar mass of SF6 = 146 g/mol
Mass of SF6 = 45.0 g
Number of mole of SF6 =..?
Number of mole = mass /Molar mass
Number of mole of SF6 = 45 /146
Number of mole of SF6 = 0.31 mol
Therefore, 0.31 mol is present in 45 g of SF6.