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Softa [21]
2 years ago
11

What is the difference between an enzyme and an inhibitor?​

Chemistry
1 answer:
ludmilkaskok [199]2 years ago
7 0
Enzyme- a substance produced by a living organism which acts as a catalyst to bring about a specific biochemical reaction
Inhibitor- a thing which inhibits someone or something
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Water is moving across a membrane from solution a into solution
leva [86]

The answer is solution a must have a lower solute concentration than solution  b.

That is when water is moving across a membrane from solution a into solution b, then solution a must have a lower solute concentration than solution  b.

When solution a have a lower solute concentration than solution  b, then water moves across a membrane from solution a into solution b.

7 0
3 years ago
How many mols are present in 5.24 x 1024 atoms of Carbon tetra fluoride?
Free_Kalibri [48]

Answer: 5.44×10226.022140857(74)×1023⋅mol−1.

Explanation: So the answer is approx. 0.10⋅mol

3 0
2 years ago
If u pour flour and sugar in one bowl is the substance a mixture atom or element
777dan777 [17]
Im pretty sure it's element
3 0
3 years ago
How are plate tectonics and the rock cycle connected
mote1985 [20]

Answer:

All igneous rocks the basis of the rock cycle are formed by plate tectonics. ... The heat from the mantle that fuels plate tectonics causes both igneous and sedimentary rocks to be turned into metamorphic rocks. The metamorphic rocks can be eroded into sedimentary rocks are remelted back into igneous.

Explanation:

8 0
2 years ago
A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?
Leno4ka [110]

Answer : The volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K

Putting values in above equation, we get:

\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L

Therefore, the volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

3 0
3 years ago
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