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3 years ago

10

CAN YALL HELP A MANS OUT FOR A QUESTION?

1 answer:

Degger [83]3 years ago

3 0

The answer is
b. mantle

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Which classes of elements can participate in iconic bonds?

Serggg [28]

Answer:

an ionic bind occurs between a metal and a nonmetal.

ex: NaCl

8 0

3 years ago

Does the radiation from the sun travel to earth in varying frequencies

Rama09 [41]

Explanation:

The gamma ray photons make their arduous journey to the surface of the Sun, they are continuously absorbed by the solar plasma and re-emitted to lower frequencies. ... By the time they get to the surface, their frequencies are mostly only within the IR/visible light/UV spectrum. Nov28,2020

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3 years ago

How many grams of oxygen are needed to

Paraphin [41]

Answer:

The value is $M_{o} = 175 g$

Explanation:

Generally the reaction between oxygen and magnesium is

$2Mg_{({s})} + O_2_{(g)} \to 2MgO_{(s)}$

Generally from the law of mass conservation in a chemical reaction we have that

$M_{m} + M_{o} = M_{z}$

Here $M_{m}$ is the mass of magnesium

$M_{o}$ is the mass of oxygen

$M_{z}$ is the mass of magnesium oxide

So

$425+ M_{o} = 600$

=> $M_{o} = 600 - 425$

=> $M_{o} = 175 g$

3 0

4 years ago

Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?

BigorU [14]

<h3>Answer:</h3>

2 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<h3>Explanation:</h3>

<u>Step 1: Define</u>

36.7 g CaF₂

300 mL H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

<u>Step 3: Convert</u>

<em>Solute</em>

Set up: $\displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})$
Multiply: $\displaystyle 0.470031 \ mol \ CaF_2$

<em>Solution</em>

Set up: $\displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})$
Multiply: $\displaystyle 0.3 \ L \ H_2O$

<u>Step 4: Find Molarity</u>

Substitute [M]: $\displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}$
Divide: $\displaystyle x = 1.56677 \ M$

<u>Step 5: Check</u>

<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>

1.56677 M ≈ 2 M

8 0

3 years ago

A lightbulb filled with argon gas has a volume of 75 mL at STP. How many moles of argon gas does the lightbulb contain?

Elan Coil [88]

Answer:

0.00335 moles

Explanation:

From the question, Using

PV = nRT................... Equation 1

Where P = pressure, V = Volume, n = number of moles of argon gas, R = Molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: P = 1 atm (standard pressure), T = 273 K (standard temperature), V = 75 mL = 0.075 dm³

Constant: R = 0.082 atm·dm³/K·mol

Substitute into equation 2

n = (1×0.075)/(273×0.082)

n = 0.075/22.386

n = 0.00335 moles

4 0

3 years ago