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3 years ago

What is the rate of change in velocity?

Physics

1 answer:

WINSTONCH [101]3 years ago

3 0

<span>The rate of change in velocity is acceleration.</span>

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Tranh slowed his skateboard as he

ICE Princess25 [194]

Answer:

Explanation:

Given parameters:

Initial velocity = 8m/s

Final velocity = 2m/s

Time taken = 3seconds

Unknown and solution:

1. Is he accelerating or decelerating?

Tranh is obviously decelerating in this period. This is negative form of acceleration in which the speed reduces as the body comes to a stop.

Deceleration is a negative change in velocity with time i.e a body is reducing its velocity as time is changing.

2. What is the value?

Mathematically;

Deceleration = $\frac{Final velocity - initial velocity}{time taken}$

Deceleration = $\frac{2 -8}{3}$

= -2m/s²

3 0

3 years ago

You put a piece of red plastic wrap over one flashlight and a piece of green plastic wrap over another. You shine the light beam

KonstantinChe [14]

Answer:

Yellow

Explanation:

<u><em>Please mark as brainliest if answer is right </em></u>

Have a great day, be safe and healthy

Thank u

5 0

3 years ago

A thin stream of water flows smoothly from a faucet and falls straight down. At one point the water is flowing at a speed of v1

MrRa [10]

Answer:

The vertical distance between these two points is 12.28 cm.

Explanation:

Given that,

Speed of water = 1.23 m/s

Diameter at lower point d'= 0.787 d

We need to calculate the speed of water

Using continuity equation

$A_{1}v_{1}=A_{2}v_{2}$

$\dfrac{\pi\times d^2}{4}v_{1}=\dfrac{\pi\times d'^2}{4}v_{2}$

$v_{2}=v_{1}\times(\dfrac{d}{d'})^2$

Put the value into the formula

$v_{2}=1.23\times(\dfrac{d}{0.787d})^2$

$v_{2}=1.98\ m/s$

We need to calculate the vertical distance h between these two points

Using Bernoulli theorem

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}$

Here, P₁ = P₂ = atmosphere pressure is same because both end is open

$\dfrac{1}{2}\rho(v_{2}^2-v_{1}^2)=\rho\times g(h_{1}-h_{2})$

$(v_{2}^2-v_{1}^2)=2g(h_{1}-h_{2})$

$2g\times\Delta h=(v_{2}^2-v_{1}^2)$

$\Delta h=\dfrac{1.98^2-1.23^2}{2\times9.8}$

$\Delta h=12.28\ cm$

Hence, The vertical distance between these two points is 12.28 cm.

6 0

4 years ago

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kodGreya [7K]

<h3>Intramolecular Forces:-</h3>

An intramolecular force (or primary forces) is any force that binds together the atoms making up a molecule or compound, not to be confused with intermolecular forces, which are the forces present between molecules.

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3 years ago

Which computational model can be applied to the total internal energy of a system with two point masses?

I am Lyosha [343]

Answer:

Explanation:

Took the test :)

4 0

3 years ago