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Evgesh-ka [11]
3 years ago
13

What is the rate of change in velocity?

Physics
1 answer:
WINSTONCH [101]3 years ago
3 0
<span>The rate of change in velocity is acceleration.</span>
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Help plz anyone ?????
Alexus [3.1K]

Answer:

Most likely, it will be harder to get strong magnets to change phase because they have more density.

3 0
3 years ago
An object begins with a speed of 20 meters per second and slows down to a speed of 10 meters per second over a time of 5 seconds
Andreyy89

Answer:

V = 6 m/s

Explanation:

Given that,

Initial speed of an object is 20 m/s

Final speed of an object is 10 m/s

Time, t = 5 s

We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

V=\dfrac{x+y}{2}\\\\\text{Putting values}\\\\V=\dfrac{20+10}{5}\\\\V=6\ m/s

So, the average speed of the object is 6 m/s.

3 0
3 years ago
Humans first traveled to the Moon in a spacecraft in 1969. What happened as the spacecraft traveled farther from Earth?
horsena [70]

Answer:

The answer is C)The force of gravity from Earth acting on the spacecraft decreased because the distance from Earth increased.

Explanation:

Gravity, a force, is dependent on the mass of the object exerting the gravity and the distance of an outside object from that object. The larger the object, the more gravity it will exert on an outside object. This force decreases as you move away from the object, but it will always still exist and never be equal to 0.

4 0
3 years ago
Read 2 more answers
Pre-Test
SSSSS [86.1K]

Answer:

the atom cannot be divided into smaller particles

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4 0
3 years ago
Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football
faltersainse [42]

Answer:

a=159.32\ m/s^2

Explanation:

It is given that,

Angular speed of the football spiral, \omega=6.9\ rev/s=43.35\ rad/s

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

v=r\omega

v=0.085\times 43.35

v = 3.68 m/s

The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(3.68)^2}{0.085}

a=159.32\ m/s^2

So, the centripetal acceleration of the laces on the football is 159.32\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
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