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3 years ago

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A mass of 4.8 kg is dropped from a height of 4.84 meters above a vertical spring anchored at its lower end to the floor. If the

spring has a height of 82 cm and a constant of 24 N/cm, how far, to the nearest tenth of a cm, is the spring compressed?

1 answer:

krek1111 [17]3 years ago

5 0

Answer:

45.6 cm

Explanation:

Let x (m) be the length that the spring is compressed. We know that when we drop the mass from 4.84 m above and compress the springi, ts gravitational energy shall be converted to spring potential energy due to the law of energy conservation

$E_g = E_p$

$mgh = 0.5kx^2$

where h = 4.84 + x is the distance from the dropping point the the compressed point, and k = 24N/cm = 2400N/m is the spring constant, g = 9.81 m/s2 is the gravitational acceleration constant. And m = 4.8 kg is the object mass.

$4.8*9.81(4.84 + x) = 0.5 * 2400 * x^2$

$47.088x + 227.906 = 1200x^2$

$1200x^2 - 47.088x - 227.906 = 0$

$x = 0.456m$ or 45.6 cm

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