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2 years ago

Test Due! Which statement is true?

Physics

1 answer:

Lubov Fominskaja [6]2 years ago

8 0

The correct answer is C. Mercury and Mars have the same gravitational force

Explanation:

This chart compares the different features of two planets in our solar system (Mercury and Mars). In this chart, the only numerical value or feature that is the same for both planets is gravity because for both planets gravity is 1.7 m/s2. This implies the gravitational force or the force that attracts objects towards the center of the planet is the same or that objects are pulled with the same force in both planets. Moreover, this factor depends on others such as mass, density, among others.

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At a place where an object is thrown vertically downward with a speed of while a different object is thrown vertically upward wi

Bumek [7]

Answer:

Both objects will undergo the same change in velocity

Explanation:

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of object

Any object which is falling has only the acceleration due to gravity.

$ma=\dfrac{GMm}{r^2}\\\Rightarrow a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2$

The acceleration due to gravity on Earth is 9.81364 m/s²

So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.

Hence, both objects will undergo the same change in velocity.

4 0

3 years ago

Can someone please help me? Anyone? PLEASE:(

tatuchka [14]

Answer:

There's no question-

8 0

3 years ago

A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak

GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.

From the attached figure, the x and y component of forces is given by :

$T_{1x} =-T_1 cos (20)$

$T_{2x} = T_2 cos (40)$

$mg_x = 0$

$T_{1y} = T_1 sin (20)$

$T_{2y} = T_2 sin (40)$

$mg_y= -mg$

Let $R_x$ and $R_y$ is the resultant in x and y direction.

$R_x=-T_1 cos (20)+T_2 cos (40)+0$

$R_y=T_1 sin(20)+T_2 sin(40)-mg$

As the system is balanced the net force acting on it is 0. So,

$-T_1 cos (20)+T_2 cos (40)+0=0$ .............(1)

$T_1 sin(20)+T_2 sin(40)-100\times 9.8=0$ ..................(2)

On solving equation (1) and (2) we get:

$T_1=866.86\ N$ (tension on the left rope)

$T_2=1063.36\ N$ (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.

7 0

3 years ago

A soap bubble usually pops because some part of it becomes too thin due to evaporation or drainage of fluid. The change in thick

Lapatulllka [165]

Answer:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

Explanation:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

5 0

3 years ago

An alpha particle(the nucleus of a helium atom) has a mass of 6.64*10^-27kg and a charge of +2e. What are the magnitude and dire

emmasim [6.3K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Weight = electric force
mg = qE 

6.64x10^-27 x 9.81 = (2 x 1.60x10^-19) E
qE =mg,
E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m

8 0

3 years ago

Read 2 more answers