Answer:
<h3>1. In the case of candle flame , the object is placed beyond c , that means the image is formed or focused between c and f .in second case the object or sun is at infinity , so the image will be </h3><h3>formed at focus.this means the distance between image and lens has decreased in the second </h3><h3>case. either we have to move the screen towards the lens or the lens towards the screen.</h3>
Explanation:
I have posted the drawing.
in the second image
it is project c and characteristics
hope it helps u :)
Answer:
828 kg/m³ or 0.828 g/cm³
Explanation:
Applying,
D = m/V............. Equation 1
Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.
From the question,
Given: m = 77 g , V = 93 cm³
Substitute these values into equation 1
D = 77/93
D = 0.828 g/cm³
Converting to kg/m³
D = 828 kg/m³
Answer:
The linear momentum is zero
Explanation:
Because
When a rigid body is rotating about a fixed axis passing through point O, the body’s linear momentum given as L = mvG
But VG= 0 so
Linear momentum is zero
Answer:
5.5 x 10^5 N/C
Explanation:
t = 0.001 s
Δp = - 8.8 x 10^-17 kg m /s
Force is equal to the rate of change of momentum.
F = Δp / Δt
F = (8.8 x 10^-17) / 0.001 = 8.8 x 10^-14 N
q = 1.6 x 10^-19 C
Electric field, E = F / q = (8.8 x 10^-14) / (1.6 x 10^-19)
E = 5.5 x 10^5 N/C
The possible magnitude for the force of static friction on the stationary cart is 72.1 N.
The given parameters:
- <em>Applied force on the cart, F = 72.1 N</em>
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Based on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.
F = ma
Static frictional force is the force resisting the motion of an object at rest.
where;
is the frictional force
Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.
Learn more about Newton's second law of motion: brainly.com/question/25307325
