Answer:

Explanation:
Hello.
In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

Consider that the given initial pressure is also equal to Pa:

Which stands for a pressure increase when volume decreases.
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Sodium chlorate decomposes into sodium chloride and oxygen.
The reaction is
NaClO3 --Δ--> NaCl + O2
The Δ means that heat is used
This equation is still not balanced.
Balancing the equation
2NaClO3 --Δ--> 2NaCl + 3O2
The equation is now balanced.
Answer:
Hope it helps.
Explanation:
It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131
Answer:- C) sodium has a higher ionization energy because it is smaller.
Explanations:- Ionization energy is the energy required to remove electron from valence shell of an atom in it's gaseous form.
More energy is required to remove the electron if the size of the atom is smaller as it's electrons are more strongly attracted by it's nucleus.
In periodic table, atomic size decreases on moving left to right in a period and increases on going top to bottom in a group.
Na and Cs are the elements of same group(first group) and also Cs is below Na. So, as Na is placed above Cs, the size of Na is smaller than Cs and so more energy is required to remove the electron from this smaller atom.
Hence, the right choice is C) sodium has a higher ionization energy because it is smaller.
Answer:
0.113 M
Explanation:
The reaction that takes place is:
- NaHCO₃ + HCl →NaCl + CO₂ + H₂O
First we convert 0.3967 g of NaHCO₃ into moles, using its molar mass:
- 0.3967 g ÷ 84 g/mol = 4.72x10⁻³ mol NaHCO₃
As 1 mol of NaHCO₃ reacts with 1 mol of HCl, in 41.77 mL of the HCl solution there were 4.72x10⁻³ moles of HCl.
With the <em>calculated number of moles and the given volume </em>we <u>calculate the concentration of the solution</u>:
- Converting 41.77 mL ⇒ 41.77 mL / 1000 = 0.04177 L
- Concentration = 4.72x10⁻³ mol / 0.04177 L = 0.113 M