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lisov135 [29]
3 years ago
5

To standardize a hydrochloric acid solution, it was used as a titrant with a solid sample of sodium hydrogen carbonate, NaHCO3.

The solid sample had a mass of 0.3967g, and 41.77 mL of acid was required to reach the equivalence point. Calculate the concentration of the standard solution.
Chemistry
1 answer:
Ket [755]3 years ago
6 0

Answer:

0.113 M

Explanation:

The reaction that takes place is:

  • NaHCO₃ + HCl →NaCl + CO₂ + H₂O

First we convert 0.3967 g of NaHCO₃ into moles, using its molar mass:

  • 0.3967 g ÷ 84 g/mol = 4.72x10⁻³ mol NaHCO₃

As 1 mol of NaHCO₃ reacts with 1 mol of HCl, in 41.77 mL of the HCl solution there were 4.72x10⁻³ moles of HCl.

With the <em>calculated number of moles and the given volume </em>we <u>calculate the concentration of the solution</u>:

  • Converting 41.77 mL ⇒ 41.77 mL / 1000 = 0.04177 L
  • Concentration = 4.72x10⁻³ mol / 0.04177 L = 0.113 M
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