Answer:
Approximate escape speed = 45.3 km/s
Explanation:
Escape speed
Here we have
Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²
R = 1 AU = 1.496 × 10¹¹ m
M = 2.3 × 10³⁰ kg
Substituting
Approximate escape speed = 45.3 km/s
Well I don't know. Let's actually LOOK at the picture and see if that helps.
A, B, C, and D all have the same TOTAL length, but A has the most waves crammed into that same total length.
By golly, that means the length of <u><em>each</em></u> wave in A must be shorter than each wave in B, C, or D.
The correct choice is <em> A </em>. Looking at the picture did the trick !
Explanation:
There's a massive amount, just think of anything everyday. Like a table on the floor, or when your walking around and putting pressure on the floor. When you squeeze something which is solid. Anything like that will do.
<span>A: put an atom on a poster in the exhibit
Good luck. The poster itself is made of trillions of trillions of trillions
of atoms. You could not see the extra one any easier than you could
see the ones that are already there, and even if you could, it would be
lost in the crowd.
B: use a life size drawing of an atom
Good luck. Nobody has ever seen an atom. Atoms are too small
to see. That's a big part of the reason that nobody knew they exist
until less than 200 years ago.
D: set up a microscope so that visitors can view atoms
Good luck. Atoms are way too small to see with a microscope.
</span><span><span>C: Display a large three dimensional model of an atom.
</span> </span>Finally ! A suggestion that makes sense.
If something is too big or too small to see, show a model of it
that's just the right size to see.
Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e
q/r
2
, so
E=
(5.11×10
−11
m)
2
(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)
=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.
