Answer:
I think it will be half of the initial charge
Explanation:
Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2
Answer:
Rmax = 3.4 10⁶ m
Explanation:
For this exercise we will use the concept of energy
Initial. On the surface of the luma
Em₀ = K + U
Em₀ = ½ m v² - G m M / R_moon
Final. At the furthest point
Emf = U
Emf = - g m M / R_max
Em₀ = Emf
½ m v² - G m M / R_moon = - G m M / R_max
½ v² + G M (-1 / R_moon + 1 / R_max) = 0 (1)
Let's use the fact that tells us that the speed of the rocket is equal to the speed of a satellite that rotates around the moon near the surface, let's use Newton's second law
F = m a
Acceleration is centripetal
a = v² / r
r= R_moon
G m M / R_moon² = m v² / R_mon
G M / R_moon = v²
We substitute in 1
½ G M / R_moon + G M (1 / R_max - 1 / R_moon) = 0
1 / R_max = 1 / R_moon (1- ½)
R_max = R_moon 2
Rmax = 2 1700 103
Rmax = 3.4 10⁶ m
A roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceleration
