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AfilCa [17]
3 years ago
13

PLEASE HELP ASAP

Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:A skier could benefit from a sports-specific training program because it could help them become better at skiing. ... Other activities such as squats and lunges will also improve skiing skills since it builds up lower body strength which is necessary to ski tough terrain.

Explanation:

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If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 46
Butoxors [25]
92 grams of Y would combine with 46 grams of X
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3 years ago
A 32-ounce stack of paper is at a temperature of 65°F. Then the paper is divided into fourths. The amount of thermal energy in e
Yakvenalex [24]
C because the stack of paper was divided into 4
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3 years ago
If 8.65 g of a tin - fluorine compound contains 5.28 g of tin, what is its empirical formula?
allsm [11]
First, we need to know the amounts of the elements in the compound.

Tin (Sn)= 5.28 g
Fluorine (F) = 8.65 - 5.28 = 3.37 g

Convert these to units of moles by dividing the molar masses.

Tin (Sn)= 5.28 g / 118.71 g/mol = 0.044 mol
Fluorine (F) = 3.37 g / 19.00 g/mol = 0.177 mol

Divide both by the least number of moles of the two.


Tin (Sn)= 0.044 mol /  0.044 mol = 1
Fluorine (F) =  0.177 mol / 0.044 mol = 4

Therefore, the empirical formula would be:
SnF4
4 0
2 years ago
Read 2 more answers
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an
a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, \mu=6\times 10^{-2}

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

KE=PE+W

\dfrac{1}{2}mv^2=mgh+W

W is the work done by the friction.

W=f\times d

f=\mu mg\ cos\theta

W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}

W=\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}

\dfrac{1}{2}v^2=9.8\times 3.1+\dfrac{6\times 10^{-2}\times 9.8\times 3.1}{tan(30)}

v = 8.19 m/s

So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0
2 years ago
A ball rolls from x=3.85m to x=22.1m in 5 seconds. What was its average velocity
Vadim26 [7]

Answer:

Average Velocity = 3.65 m/s

Explanation:

Average Velocity  =\frac{Total   Displacement}{Total     Time} =\frac{22.1-3.85}{5}=\frac{18.25}{5}=3.65

3 0
2 years ago
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