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2 years ago

A swimmer swims faster and increases from 80.1m/s to 80.3 m/s during the last 20 seconds. What is the Final Velocity?

Physics

1 answer:

Maurinko [17]2 years ago

8 0

Answer:

0.01 m/s^2.

Explanation:

The formula for acceleration is Δ velocity/ Δ time or change in velocity/change in time. We can see find the change in velocity by subtracting v0 (initial velocity) from v (current velocity). v - v0 = 80.3 m/s - 80.1 m/s = 0.2 m/s. The change in time is already given, 20 seconds, so all you have to do is divide 0.2 m/s by 20 seconds to get 0.01 m/s^2.

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A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet

marin [14]

Answer:

option A is correct

Explanation:

Given:

The length to be painted = m miles

The width to be painted = t inches

Area painted in 1 gallon = p square feet

Converting the every given dimension in feet, we have

length to be painted = m × 5280 feet

width to be painted = t/12 feet

area to be painted = (m × 5280 feet) × t/12 feet

now, applying the unitary method, we have

p square feet is painted ⇒ 1 gallon

1 square feet is painted ⇒ 1/p gallon

(m × 5280 feet) × t/12 feet square feet is painted ⇒ [(m × 5280 feet) × t/12 feet ] × 1/p gallon

thus, we get the gallons of paint required as 5820 mt/12p

hence option A is correct

3 0

3 years ago

The angular width of localizers varies between ______ and ______ degrees in order to provide a signal width of approximately 700

natali 33 [55]

Answer: 10 and 35 degrees

Explanation: Localizers width below 10 degree and 35 degree signal arc is unreliable and considered unusable for navigation and as a result, aircrafts may loose alignment

5 0

3 years ago

if a piece of sea floor has moved 50 km in 5 million years what is the yearly rate of sea-floor motion?

BartSMP [9]

<span>0.0001 km / year or 10^-5 km/year just take 50 km and divide it by 5 million</span>

6 0

3 years ago

Read 2 more answers

Here is more points drip students - drip king

levacccp [35]

Answer
Thanks
Explanation

4 0

3 years ago

Read 2 more answers

A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is

Rudik [331]

Answer:

$a=16.2m/s^{2}$

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

$F=masin\alpha -\frac{kQq}{r^{2}} \\\alpha =35^{0}, m=0.495kg, r=0.61m, Q=2.5*10^{-6}, q=75.0*10^{-6}\\$

When fixed,F=o

Hence

$masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}$

The value of the acceleration is 16.2m/s^2

7 0

3 years ago