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geniusboy [140]
2 years ago
12

A swimmer swims faster and increases from 80.1m/s to 80.3 m/s during the last 20 seconds. What is the Final Velocity?

Physics
1 answer:
Maurinko [17]2 years ago
8 0

Answer:

0.01 m/s^2.

Explanation:

The formula for acceleration is Δ velocity/ Δ time or change in velocity/change in time. We can see find the change in velocity by subtracting v0 (initial velocity) from v (current velocity). v - v0 = 80.3 m/s - 80.1 m/s = 0.2 m/s. The change in time is already given, 20 seconds, so all you have to do is divide 0.2 m/s by 20 seconds to get 0.01 m/s^2.

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A student attaches a rope to his
erastova [34]

The choices are:

a. Normal Force

b. Gravity Force

c. Applied Force

d. Friction Force

e. Tension Force

​f. Air Resistance Force

Answer:

The answer is letter e, Tension Force.

Explanation:

Force refers to the "push" and "pull" of an object, provided that the object has mass. This results to acceleration or a change in velocity. There are many types of forces such as <em>Normal Force, Gravity Force, Applied Force, Friction Force, Tension Force and Air Resistance Force.</em>

The situation above is an example of a "tension force." This is considered the force that is being applied to an object by strings or ropes. This is a type force that allows the body to be pulled and not pushed, since ropes are not capable of it. In the situation above, the tension force of the rope is acting on the bag and this allows the bag to be pulled.

Thus, this explains the answer.

6 0
3 years ago
the ratio of the energy per second radiated by the filament of a lamp at 250k to that radiated at 2000k, assuming the filament i
Naily [24]

Answer:

(a) \frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b) P =  0.816 Watt

Explanation:

(a)

The power radiated from a black body is given by Stefan Boltzman Law:

P = \sigma AT^4

where,

P = Energy Radiated per Second = ?

σ = stefan boltzman constant = 5.67 x 10⁻⁸ W/m².K⁴

T = Absolute Temperature

So the ratio of power at 250 K to the power at 2000 K is given as:

\frac{P_{250k}}{P_{2000k}}=\frac{\sigma A(250)^4}{\sigma A(2000)^4}\\\\\frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b)

Now, for 90% radiator blackbody at 2000 K:

P = (0.9)(5.67\ x\ 10^{-8}\ W/m^2.K^4)(1\ x\ 10^{-6}\ m^2)(2000\ K)^4

<u>P =  0.816 Watt</u>

7 0
3 years ago
What is the net force at the equilibrium point? Derive an equation for the location of the equilibrium point based on the accele
Vitek1552 [10]

To find a general equilibrium point for a spring based on the hook law, it is possible to start from the following premise:

Hook's law is given by:

F = k\Delta X

Where,

k= Spring Constant

\Delta X = Change in Length

F = Force

When there is a Mass we have two force acting at the System:

W= mg

Where W is the force product of the weigth. Then the force net can be defined as,

F_{net} = F+W

But we have a system in equilibrium, so

0 = K\Delta X -mg

We find the equilibrium for any location when

\Delta X = \frac{mg}{k}

4 0
3 years ago
Please list them from top to bottom, for exp like in your response, a,g,q,d. Giving quite some points for it.
Aleks04 [339]
D,f,g,h,i,a,e,c,j. I’m sure that it
7 0
2 years ago
Calculating Net Force
VARVARA [1.3K]

Explanation:

225=m (2.20m/s2 which give m=16kg I used newtons second law to fins the required average force

6 0
3 years ago
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