magnetic field due to a finite straight conductor is given by
here since it forms an equilateral triangle so we will have
also the perpendicular distance of the point from the wire is
now from the above equation magnetic field due to one wire is given by
now since in equilateral triangle there are three such wires so net magnetic field will be
The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;
The magnification of the lens is found as;
Hence, the image distance and magnification of The image will be 30 cm and 3.
To learn more about the focal length refer;
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