Answer:
D. circumpolar
Explanation:
A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.
-Wikipedia
Answer:
10 J.
Explanation:
Given that,
Net force acting on the rake, F = 2 N
Distance moved by the rake, d = 5 m
We need to find the kinetic energy gained by the rake. We know that,
Kinetic energy = work done
So,
K = F×d
K = 2 N × 5 m
K = 10 J
So, 10 J of kinetic energy is gained by the rake.
Answer:
The correct option is E. X(g) → X⁺(g) + e⁻
Explanation:
The electrons are attracted to the nucleus and it is necessary to provide energy to start them. Then the ionization energy is the energy necessary to pull an electron to a gaseous atom, isolated and in a fundamental state. The electrons in the last shell are the most weakly attracted to the nucleus, so these are the lost electrons.
In this way, the gaseous element is converted to a gaseous cation (positively charged ion).
Taking this definition into account, <u><em>the correct option is E. X(g) → X⁺(g) + e⁻</em></u>
When we say "<span>The moon's surface gravity is one-sixth that of the earth.",
we mean that the acceleration of gravity on the Moon's surface is 1/6 of
the acceleration of gravity on the Earth's surface.
The acceleration of gravity is (9.8 m/s</span>²) on the Earth's surface, so
<span>it would be (9.8/6 m/s</span>²) on the Moon's surface.
<span>
The weight of any object, right now, is
(object's mass) </span>· (acceleration of gravity where the object is located now) .
<span>
If the object's mass is 24 kg and the object is on the Moon right now,
then its weight is
(24 kg) </span>· (9.8/6 m/s²)
= (24 · 9.8 / 6) kg-m/s²
= 39.2 Newtons
Answer:
E = F/ q 8x10^17÷ 1.6 x 10^ - 19
Explanation:
5x 10^36N\c A is answer
