The object will come to a halt.
Resultant force at start:17-10=7 to the left
When additional force is added to the right,it balances the forces acting in the object.
7N to the right and 7N to the left suggests that the object will come to a halt as it is in equilibrium.
Answer:
A. 148.23 m
B. 2.75 m/s
Explanation:
The following data were obtained from the question:
Time of flight (T) = 11 s
Maximum height (h) =?
Initial velocity (u) =?
Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:
Time of flight (T) = 11 s
Time (t) to reach the maximum height =.?
T = 2t
11 = 2t
Divide both side by 2
t = 11/2
t = 5.5 s
NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.
A. Determination of the maximum height to which the ball was thrown.
Time (t) to reach maximum height = 5.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 5.5²
h = 4.9 × 30.25
h = 148.23 m
B. Determination of the initial velocity.
Maximum height (h) reached = 148.23 m
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
u² = h/2g
u² = 148.23 / (2 × 9.8)
u² = 148.23 / 19.6
Take the square root of both side
u = √(148.23 / 19.6)
u = 2.75 m/s
Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
Answer:
Correct answer: P₂ = 25 W
Explanation:
Given: voltage V₁ = 220 V, power P₁ = 100 W, V₂ = 110 V, P₂ = ?
The formula for calculating power is:
P = V · I
We will include in the story and ohm's law:
I = V/R
We will replace the current in the expression for power
P = V · V/R = V²/R ⇒ R = V²/P
We will first calculate the electrical resistance of the bulb which is a constant in the electrical circuit
R = V₁²/P₁ = 220²/ 100 = 48,400 / 100 = 484 Ω
Power consumption of bulb connected to 110 V is:
P₂ = V₂²/R = 110²/484 = 12,100/484 = 25 W
P₂ = 25 W
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