Answer:
![q_2=2.47\times 10^{-4}\ C](https://tex.z-dn.net/?f=q_2%3D2.47%5Ctimes%2010%5E%7B-4%7D%5C%20C)
Explanation:
The charge on one object, ![q_1=9.9\times 10^{-5}\ C](https://tex.z-dn.net/?f=q_1%3D9.9%5Ctimes%2010%5E%7B-5%7D%5C%20C)
The distance between the charges, r = 0.22 m
The force between the charges, F = 4,550 N
Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :
![F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Br%5E2%7D%5C%5C%5C%5Cq_2%3D%5Cdfrac%7BFr%5E2%7D%7Bkq_1%7D%5C%5C%5C%5Cq_2%3D%5Cdfrac%7B4550%5Ctimes%20%280.22%29%20%5E2%7D%7B9%5Ctimes%2010%5E9%5Ctimes%209.9%5Ctimes%2010%5E%7B-5%7D%7D%5C%5C%5C%5Cq_2%3D2.47%5Ctimes%2010%5E%7B-4%7D%5C%20C)
So, the charge on the other sphere is
.
The answer is B tell me if I am wrong.
The answer is a because if you look really close
Answer:
+131Joules
Explanation:
Energy can be expressed using below expresion.
ΔE = (q + w).........eqn(1)
q will be + be if heat is gained hence, q= 240 J
work "w" will be - ve if work is done by the system, hence w= -109 J
Then substitute into eqn(1)
Change in Internal energy=
= (240 -109 )
= +131J