Answer:
30.93 m/s
Explanation:
Given that, the speed of stolen car is,
As policeman start chasing the stolen car after 60 seconds.
Now suppose the speed of policeman car is,
The policeman catches the stolen car at a distance of,
Now the distance covered by the policeman in time t is
And the distane cover by the thief in stolen car in time(t+60s) is .
And these distances are equal and they are equal to 60000 m.
Therefore,
Therfore,
Now use this value to solve for minimum speed of policeman's car.
Therefore minimum speed of policeman's car is 30.93 m/s.
I think the answer you or looking for is miter saw please tell me if I’m wrong
C. 0.37V. A capacitor of 650x10⁻⁴F that stores 24x10⁻³C has a potential difference of 0.37V between its plates.
The key to solve this problem is using the capacitance equation C = Q/Vᵃᵇ, where C is the capacitance, Q the charge stored in the plates, and Vᵃᵇ the potential difference between the plates.
A 650x10⁻⁴F capacitor stores 24x10⁻³C, clear Vᵃᵇ for the equation:
C = Q/Vᵃᵇ -----------> Vᵃᵇ = Q/C
Solving
Vᵃᵇ = 24x10⁻³C/650x10⁻⁴F = 0.37V
Answer:
The velocity of the boy and the bicycle is 2.2 m/s.
Explanation:
We have,
Mass of child is 30 kg and the mass of bicycle is 20 kg. The combined momentum of the child and the bicycle is 110 kg-m/s.
It is required to find the velocity of the boy and the bicycle. The momentum of an object is given in terms of mass and its velocity. So,
M is combined mass of child and bicycle
So, the velocity of the boy and the bicycle is 2.2 m/s.
Answer and Explanation
Arranging the measured values in increasing order;
4.3s, 4.6s, 4.6s, 4.8s, 5.1s, 5.8s
The two outliers are obviously 4.3s and 5.8s; An outlier is a value in a statistical sample which does not fit a pattern that describes most other data point. Outliers make the average value complicated. So, it is usually better for data to be precise with data points spreading out around a small area.
So, the mean is the average of the four remaining data points after removing the outliers.
Mean = (4.6 + 4.6 + 4.8 + 5.1)/4
Mean = 4.775s
So, the value recorded should be 4.775s, 4.78s or 4.8s depending on the number of decimal places allowed.
QED!