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3 years ago

Covalent Bonds usually bond atoms of which type of elements together?

Physics

1 answer:

anzhelika [568]3 years ago

5 0

<h2>Answer: Nonmetals to Nonmetals </h2>

Covalent bonds hold non-metallic atoms together. These atoms have many electrons in their outermost level and have a tendency to gain electrons rather than to yield them.

In this case the bond is formed by sharing a pair of electrons between the two atoms, one from each atom. Then, this pair of shared electrons is common to the two atoms and holds them together, so that both atoms acquire more stability.

Therefore the correct answer is C.

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A moving object has a kinetic energy of 20 J. if it’s velocity doubles, it’s kinetic energy would be

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Applying the formula, we see that the ke gets increased 4 tines.

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3 years ago

Which factor should change when comparing the boiling times of the liquids?

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3 years ago

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A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?

GalinKa [24]

Answer:

The electric flux through the sphere is $8.58 *10^{5} \frac{Nm^2}{C}$

Explanation:

Given

$Radius,\ r = 0.03m\\Charge,\ q =7.6\µC$

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε $= 8.8542 * 10^{-12}$

Substitute ε $= 8.8542 * 10^{-12}$ and $q =7.6\µC$ ; The formula becomes

Ф = $\frac{7.6\µC}{8.8542 * 10^{-12}}$

Ф = $\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}$

Ф = $\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}$

Ф = $\frac{7.6}{8.8542} *10^{12-6}}$

Ф = $0.85834970974 *10^{12-6}}$

Ф = $0.85834970974 *10^{6}}$

Ф = $8.5834970974 *10^{5}}$

Ф = $8.58 *10^{5} \frac{Nm^2}{C}$

Hence, the electric flux through the sphere is $8.58 *10^{5} \frac{Nm^2}{C}$

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3 years ago

Which of the following is a definition of motion?

Murrr4er [49]

Answer:

sorry I don't get it so pls can u repeat the question .

Movement of any object from one position to another position with respect to the observer is called as Motion. Motion Along a Straight Line: When an object moves along a straight line, the motion of the object is called rectilinear motion. For example; motion of a car on highway.

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3 years ago

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A 1325 kg car and a 2050 kg pickup truck approach a curve on a highway that has a radius of 255 m. At what angle should the high

Scorpion4ik [409]

Answer:

the banking angle of the road is 24.2⁰

Explanation:

Given;

speed of the vehicles considered, v = 75 mi/h

Speed in m/s ⇒ 1 mi/h --------> 0.44704 m/s

75 mi/h --------> ?

= 75 x 0.44704 m/s = 33.528 m/s

radius of the curve, r = 255 m

The banking angle of the road is calculated as;

$\theta = tan^{-1} (\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{33.528^2}{255\times 9.8} )\\\\\theta = tan^{-1}(0.44983)\\\\\theta =24.2^0$

Therefore, the banking angle of the road is 24.2⁰

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3 years ago