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3 years ago

11

in addition to studies of the body system of corals what studies in earth science might increased scientists understanding of an

ability to predict coral bleaching

1 answer:

Maru [420]3 years ago

6 0

Answer: they could get a piece of the coral and run tests on it

Explanation:

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Two equally charged tiny spheres of mass 1.0 g are placed 2.0 cm apart. When released, they begin to accelerate away from each o

zhannawk [14.2K]

Answer:

The magnitude of the charge on each sphere is 0.135 μC

Explanation:

Given that,

Mass = 1.0

Distance = 2.0 cm

Acceleration = 414 m/s²

We need to calculate the magnitude of charge

Using newton's second law

$F= ma$

$a=\dfrac{F}{m}$

Put the value of F

$a=\dfrac{kq^2}{mr^2}$

Put the value into the formula

$414=\dfrac{9\times10^{9}\times q^2}{1.0\times10^{-3}\times(2.0\times10^{-2})^2}$

$q^2=\dfrac{414\times1.0\times10^{-3}\times(2.0\times10^{-2})^2}{9\times10^{9}}$

$q^2=1.84\times10^{-14}$

$q=0.135\times10^{-6}\ C$

$q=0.135\ \mu C$

Hence, The magnitude of the charge on each sphere is 0.135μC.

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3 years ago

Why do aeroplanes take longer to fly west than east?

PolarNik [594]

Every planet/moon has global wind that are mostly determined by the way the planet/moon rotates and how evenly the Sun illuminates it. On the Earth the equator gets much more Sun than the poles. resulting in warmer air at the equator than the poles and creating circulation cells (or "Hadley Cells") which consist of warm air rising over the equator and then moving North and South from it and back round.

The Earth is also rotating. When any solid body rotates, bits of it that are nearer its axis move slower than those which are further away. As you move north (or south) from the equator, you are moving closer to the axis of the Earth and so the air which started at the equator and moved north (or south) will be moving faster than the ground it is over (it has the rotation speed of the ground at the equator, not the ground which is is now over). This results in winds which always move from the west to the east in the mid latitudes.

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A simple pendulum having a length of 1.02 m and a mass of 6.66 kg undergoes simple harmonic motion when given an initial speed o

attashe74 [19]

Answer:

<em>Time period of pendulum is 2.02 s.</em>

Explanation:

A <em>simple pendulum</em> is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.

The time period of pendulum is defined as time taken by the pendulum to complete one full oscillation . it is denoted by T.

By <em>Huygens law of period of pendulum</em>,

T = 2π $\sqrt{\frac{L}{g} }$ eqn 1

where L is the length of pendulum,

g is acceleration due to gravity

<em>Period of pendulum is independent of the mass of pendulum,</em>

<em />

Substituting values in eqn 1

T = 2π $\sqrt{\frac{1.02}{9.8\\} }$

T = 2.02 s

<em>Time period of pendulum is 2.02 s.</em>

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