Answer:
For any given isotope, the sum of the numbers of protons and neutrons in the nucleus is called the mass number. This is because each proton and each neutron weigh one atomic mass unit. By adding together the number of protons and neutrons and multiplying by 1, you can calculate the mass of the atom.
Answer:
V2 = 17371.43ml
Explanation:
We use Boyles laws
since temperature is constant
P1V1=P2V2
760 x 400 = 17.5 x V2
304000 = 17.5 x V2
V2 = 304000/17.5
V2 = 17371.43ml
Polarity is the chemical property based on the electric charge and orientation of the poles. Al−O>H−Br>As−S is arranged in decreasing order of polarity. Thus, option d is correct.
<h3>What is polarity?</h3>
Polarity is a chemical property of the distribution of the electrical charges over their respective atom in the molecule joined by the bonds. The relation between the polarity and the difference in electronegativity is directly proportional.
The electronegativity difference between the elements are:
- Al−O = 1.8
- H−Br = 0.8
- As−S = 0.4
As the electronegativity difference between Al−O = 1.8 is the highest it will have the highest polarity followed by H−Br = 0.8, and As−S = 0.4, with the lowest polarity.
Therefore, option D. Al−O>H−Br>As−S is arranged in decreasing order of polarity.
Learn more about electronegativity here:
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Answer:
mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g
Explanation:
The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula
K = concentration of X in ether/concentration of X in water
Partition coefficient, K(X) between ethoxy ethane and water = 40
Concentration of X in ether = mass(g)/volume(dm³)
Mass of X in ether = m g
Volume of ether = 50/1000 dm³ = 0.05 dm³
Concentration of X in ether = (m/0.05) g/dm³
Concentration of X in water = mass(g)/volume(dm³)
Mass of X in water left after extraction with ether = (5 - m) g
Volume of water = 1 dm³
Concentration of X in water = (5 - m/1) g/dm³
Using K = concentration of X in ether/concentration of X in water;
40 = (m/0.05)/(5 - m)
(m/0.05) = 40 × (5 - m)
(m/0.05) = 200 - 40m
m = 0.05 × (200 - 40m)
m = 10 - 2m
3m = 10
m = 10/3
m = 3.33 g of X
Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g
Answer:
When a solid turns to a gas.
Explanation:
