Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
The answer is 37.5 moles
The explanation:
1- when we have the mass of SO3 in Kg so, first we have to convert it to grams:
mass = 3 * 1000 = 3000 g
2- we need to get the molar mass of SO3 :
molar mass of SO3 = 32 + (16*3)
= 80 g/mol
3- then we can use this formula to get number of moles:
moles = mass / molar mass
= 3000 g / 80 g/mol
= 37.5 moles
Answer:
I'm sure but send thru this picture for the question so I can help.
Electrons are free to move throughout metal substance, shared throughout so electricity and heat are conducted well
