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Paul [167]
3 years ago
11

Rutherford's experiment showed that subatomic particles

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

b. don't take up most of the space in an atom.

Explanation:

Rutherford’s gold foil experiment showed that most of the subatomic particles are confined in a small volume at the center nucleus of the atom. When Rutherford bombarded gold foil with alpha particles he observed that a small fraction of them deflected by 180 degree. So he concluded that the center of the atom is dense.

Nostrana [21]3 years ago
4 0
B. Don't take up most of the space in an atom,
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Explain ways that organisms interact in helpful and harmful ways.
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How does the density of a gas depend on the molar mass of the gas?
AlladinOne [14]

Answer:

The density of the ideal gas is directly proportional to its molar mass.

Explanation:

Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.

\rho = \frac{m}{V}                          ......equation (1)

According to the ideal gas law for ideal gas:

PV = nRT                                       ......equation (2)

Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas

As we know,

The number of moles: n = \frac{m}{M}

where m is the given mass of gas and M is the molar mass of the gas

So equation (2) can be written as:

PV = \frac{m}{M}RT

⇒ PM= \frac{m}{V} RT

⇒ \frac{PM}{RT}= \frac{m}{V}             ......equation (3)

Now from equation (1) and (3), we get

\frac{PM}{RT}= \frac{m}{V} = \rho  

⇒ Density of an ideal gas: \rho = \frac{PM}{RT}  

⇒ <em>Density of an ideal gas: ρ ∝ molar mass of gas: M</em>

<u>Therefore, the density of the ideal gas is directly proportional to its molar mass. </u>

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3 years ago
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The correct answer is Cl.

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