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Paul [167]
3 years ago
11

Rutherford's experiment showed that subatomic particles

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

b. don't take up most of the space in an atom.

Explanation:

Rutherford’s gold foil experiment showed that most of the subatomic particles are confined in a small volume at the center nucleus of the atom. When Rutherford bombarded gold foil with alpha particles he observed that a small fraction of them deflected by 180 degree. So he concluded that the center of the atom is dense.

Nostrana [21]3 years ago
4 0
B. Don't take up most of the space in an atom,
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Can anybody answer this question of chemistry?
maw [93]

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

4 0
2 years ago
Read 2 more answers
A. What is an atom's electron configuration?
Tju [1.3M]

Answer:

It is the distributions of electron on the three levels

Explanation:

The three levels are : K . L . M . N

5 0
3 years ago
Read 2 more answers
A new penny has a mass of 2.49 g and a volume of 0.349cm3. The density of copper is 8.94 g/mLA)Is the penny made of pure copper?
yawa3891 [41]

Answer:

Zinc metal might be mixed with the copper.

Explanation:

Density is defined as mass of the substance present in the unit volume of the substance.

Mass=\frac{Mass}{Volume}

Density of pure copper = d = 8.94 g/mL = 8.94 g/cm^3

1 mL = 1 cm^3

Mass of the copper penny = M = 2.49 g

Volume of the copper penny = V = 0.349 cm^3

Density of the copper penny = d

d=\frac{M}{V}=\frac{2.49 g}{0.349 cm^3}=7.135 g/cm^3

Density of pure copper > Density of zinc > Density of penny

8.94 g/cm^3>7.14 g/cm^3>7.135 g/cm^3

The metal mixed with copper is zinc to make a penny . This is so because all the other metal given have higher value of density which will increase the density of the copper penny if they were present.

But here the density of the copper penny is smaller than density of pure copper which means that less denser metal than copper is also added in the penny.

3 0
3 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

6 0
3 years ago
You have 2 moles of NaOH how many molecules of NaOH?
kaheart [24]

Answer:

12.044 X 10^23 molecules of NaOH

Explanation:

because NaOH is an ionic bond, we should be asking how many <em>formula units </em> are in 2 moles of NaOH, there are 0 molecules since NaOH is measured in formula units.

but for the sake of the problem I'll assume NaOH is measured in molecules

for every mol of something there are 6.022 X 10^23 of something of that something.

so there are 6.022 X 10^23 molecules for every mol of NaOH

that means we have 2 X 6.022 X 10^23 molecules in 2 moles of NaOH = 12.044 X 10^23 molecules of NaOH

4 0
3 years ago
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