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3 years ago

6

Naoki's bicycle has a mass of 11 kg. If Naoki sits on her bicycle and starts pedaling with a force of 197.2 N, causing an accele

ration of 2.9 m/s2, what is Naoki's mass?

1 answer:

Cloud [144]3 years ago

7 0

yes 89.75 sorry I'm not the best at math you should look on the internet

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What is the balenced equation of Cu+H2SO4---> CuSO4+H2O+SO2

algol [13]

Balanced chemical equation :

1 Cu + 2 H2SO4 = 1 CuSO4 + 2 H2O + 1 SO<span>2</span>

hope this helps!.

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3 years ago

If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?

enyata [817]

<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.

b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.

</span>and % will be 60%.

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3 years ago

You leave a piece of bread outside for a few days. It forms green and blue mold. It smells awful. A chemical change has occurred

Fed [463]

False. It is a physical change because the molecules of the bread didn't change only the form of the bread changed.

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3 years ago

Read 2 more answers

If ch4 and c4h8 are released simultaneously at ends of a 50.0cm long glass tube, at what distance from the left end of the tube

Keith_Richards [23]

Answer:

They meet at the distance of 32.5 cm

Explanation:

The rate of diffusion is inversely proportional to the molar mass of gases.

If diffusion is represented as d and mass of gases as M. Then , rate is given as:

$d=k\sqrt{\frac{1}{M}}$

For , two gases

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

First , Calculate the ,molar mass of each gas :

CH4 = 1 (mass of C) + 4(mass of H)

= 1(12)+4(1)

= 12 + 4 = 16 gram

M1 = 16 gram

C4H8 = 4(mass of C) + 8(Mass of H)

= 4(12) + 8(1)

= 48 + 8

M2 = 56 grams

d1 is diffusion of CH4

d2 = diffusion of C4H8

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{56}{16}$ }

$\frac{d_{1}}{d_{2}} = 1.87$

This means CH4 diffuse 1.87 times faster than C4H8

Now, the mathematical part

If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec

v1 = 1.87 cm/sec

v2 = 1 cm/sec

Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8

(see the attached image)

$time =\frac{distance}{speed}$

since both meet at same time so t = constant.

$\frac{s1}{v1}=\frac{s2}{v2}$

$\frac{x}{1.87}\frac{50-x}{1.00}$

on solving for x we get,

x = 17.42 cm

from the other side the distance is (50 - x)

= 50 - 17.42 = 32.5 cm

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3 years ago

A 1 m ID spherical cooler made of 2 cm thick foam insulation (k = 0.15 Wm-1K-1) is used to store iced water at 0°C. The tank is

Leto [7]

The answer is unknown

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3 years ago