If there were an element above fluorine in the periodic table what phase would you expect it to be in (at room temp)?
1 answer:
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Answer:
14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.
Explanation:
You know:
CaCO₃ → CaO + CO₂
In the first place, by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) the following quantities react and are produced:
- CaCO₃: 1 mole
- CaO: 1 mole
- CO₂: 1 mole
Being:
- Ca: 40 g/mole
- C: 12 g/mole
- O: 16 g/mole
the molar mass of the compounds participating in the reaction is:
- CaCO₃: 40 g/mole + 12 g/mole + 3*16 g/mole= 100 g/mole
- CaO: 40 g/mole + 16 g/mole= 56 g/mole
- CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
Then, by stoichiometry of the reaction, the following mass amounts of the compounds participating in the reaction react and are produced:
- CaCO₃: 1 mole* 100 g/mole= 100 g
- CaO: 1 mole* 56 g/mole= 56 g
- CO₂: 1 mole* 44 g/mole= 44 g
You can then apply the following rule of three: if by stoichiometry of the reaction 100 grams of calcium carbonate CaCO₃ produce 56 grams of calcium oxide CaO, 25 grams of CaCO₃ how much mass of CaO will it produce?
mass of calcium oxide= 14 grams
<em><u> 14 grams of calcium oxide would be produced by thermal decomposition of 25 grams of calcium carbonate.</u></em>
Answer:
The percent yield of a reaction is 85.04%
Explanation:
Mass of = 47.5g
Molar mass of = 232 g/mole
Molar mass of = 18 g/mole
Volume of water obtained from the reaction , V= 9.40mL
Mass of water = m = Experimental yield of water
Density of water = d = 1.00 g/mL
Moles of tungsten(VI) oxide =
According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2047 moles of tungsten(VI) oxide will give:
Mass of 0.6141 moles of water:
0.6141 mol × 18 g/mol = 11.054 g
To calculate the percentage yield of reaction , we use the equation:
% yield = {
The percent yield of a reaction is 85.04%