The amount of HCl required for one experiment - 13.5 µl
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L
since one experiment uses up - 13.5 x 10⁻⁶ L
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L = 1.8 x 10⁴ times
the experiment can be carried out 18000 times
<u>The given reaction is:</u>
F2 + ClO2 → 2FClO2
Rate = k[F2][ClO2]
<u>Explanation:</u>
The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step
Step 1: F2 + ClO2 → FClO2 + F ----------- Slow
Step 2: F + ClO2 → FClO2 ----------- Fast
-----------------------------------------------------------
Overall: F2 + 2ClO2 → 2FClO2
Rate = k[F2][ClO2]
Answer:
<em><u>0.0365 is your answer</u></em>
Explanation:
<h3>hope it will help u</h3>
Natural Gases, Water, Oil, Metals, Stone
