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blagie [28]
2 years ago
15

Calculate the work when a cylinder equipped with a piston changes volume from 0.200 L to 0.600 L against an external pressure of

3.00 atm (Remember that 101.3 J = 1 L∙atm)
Chemistry
1 answer:
NISA [10]2 years ago
4 0

Answer:

-121.56\ \text{J}

Explanation:

V_1 = Initial volume = 0.2 L

V_2 = Final volume = 0.6 L

P = Pressure = 3 atm

W=-P\Delta V\\\Rightarrow W=-3(V_2-V_1)\\\Rightarrow W=-3(0.6-0.2)\\\Rightarrow W=-1.2\ \text{L atm}

1\ \text{L atm}=101.3\ \text{J}\\\Rightarrow -1.2\ \text{L atm}=-1.2\times 101.3\ \text{J}=-121.56\ \text{J}

Work done is -121.56\ \text{J}.

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Answer:

The conversion achieved for the first CSTR impeller is 0.382

Discrepancy = 0.188

Explanation:

The impeller divides the CSTR into 2 equal reactors of volume 500gal

Using V = FaoX/ (-ra)

500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]

500gal = CaoVoX1/ KCao^2(1-X1)

500gal= 500gal × X1'/(1 - X1)^2

(1 -X1)^2 = X1

X1^2 - 3X1 + 1 = 0

X1= 0.382

Conversion achieved in the first CSTR is 0.382

Actual measured CSTR = 57% =57/100=0.57

Discrepancy in the conversions= 0.57 -0.383 =0.188

8 0
3 years ago
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Answer:

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Explanation:

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Chem help 36 and 37 the word cut off on 37 is larger​
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3 years ago
If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant
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Answer:

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Explanation:

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