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3 years ago

Identify the four main divisions of the peripheral nervous system and explain each one's function.

Physics

2 answers:

Nataly [62]3 years ago

8 0

Answer:

That's correct ^-^

guajiro [1.7K]3 years ago

3 0

Answer:

The peripheral nervous system is divided into the somatic and autonomic nervous systems, and the autonomic nervous system is divided into the sympathetic and parasympathetic nervous systems. The somatic nervous system controls voluntary skeletal muscles. The autonomic nervous system controls the glands and the muscles of the internal organs. The sympathetic nervous system arouses the body and expends energy. It is responsible for our fight and flight response. The parasympathetic nervous system calms the body and conserves energy. It is responsible for our rest and digest response.

Explanation:

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On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

7 0

3 years ago

A guitar string vibrates at a frequency of 330Hz with wavelength 1.40m. The frequency and wavelength of this sound wave in air (

bixtya [17]

Answer:

Same frequency, shorter wavelength

Explanation:

The speed of a wave is given by

$v=f\lambda$

$\lambda=\dfrac{v}{f}$

where,

f = Frequency

$\lambda$ = Wavelength

It can be seen that the wavelength is directly proportional to the velocity.

Here the frequency of the sound does not change.

But the velocity of the sound in air is slower.

Hence, the frequency remains same and the wavelength shortens.

7 0

3 years ago

You need to produce a set of cylindrical copper wire 3.5 m long that will have a

vazorg [7]

Solution :

We know, resistance is given by :

$R = \dfrac{\rho l}{A}$

$A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2$

Now, we know mass of wire is given by :

$Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram$

Hence, this is the required solution.

8 0

2 years ago

Two point charges, initially 2.0 cm apart, experience a 1.0 N force. If they are moved to a new separation of 0.25 cm, what is t

den301095 [7]

Explanation:

Th electric force between charges is inversely proportional to the square of distance between them. It means,

$F\propto \dfrac{1}{r^2}$

Initial distance, r₁ = 2 cm

Final distance, r₂ = 0.25 cm

Initial force, F₁ = 1 N

We need to find the electric force between charges if the new separation of 0.25 cm. So,

$\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N$

So, the new force is 64 N if the separation between charges is 64 N.

7 0

2 years ago

If an element loses one electron and gains two neutrons, then it is considered

vaieri [72.5K]

Answer:

It would become an ion and an isotope

Explanation:

If an atom loses an electron regardless of how many neutrons you add its an ion, It gained neutrons but it still has the same number of protons so it's an isotope.

3 0

3 years ago