Explanation:
Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.
Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.
No. of moles =
= 
= 0.2 mol
Molarity of acetic acid is calculated as follows.
Density = 
1 g/ml = 
volume = 100 ml
Hence, molarity = 
= 
= 2 mol/l
As reaction equation for the given reaction is as follows.

So, moles of NaOH = moles of acetic acid
Let us suppose that moles of NaOH are "x".
(as 1 L = 1000 ml)
x = 20 L
Thus, we can conclude that volume of NaOH required is 20 ml.
Given teh equation adn the heat of reaction, reaction 2's heat of reaction can be obtained by simply multiplying teh heat of reaction of 1 by 3. The final answer is -6129 kJ.
Answer:
B
Explanation:
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Answer:
54.72 g
Explanation:
Mass = ?
Volume = 5.61 L
Pressure = 5.66 atm
Temperature = 311 K
The relationship between these equations is given by the ideal gas equation;
PV = nRT
where R = gas constant = 0.0821 atm L K-1 mol-1
n = PV / RT
n = 5.66 * 5.61 / (0.0821 * 311 )
n = 1.2436 mol
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g
Answer:
There are total 8 bonding electrons 6 frm the both Carbons and 2 from both hydrogens.
Explanation: