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Studentka2010 [4]
3 years ago
11

Which is the MOST accurate description of diffusion of materials through the cell membrane in order to maintain homeostasis?

Chemistry
2 answers:
Lelechka [254]3 years ago
8 0

Answer:

The correct answer will be option-D

Explanation:

Diffusion is the process of the movement of solute particles on the basis of the concentration gradient.

During homeostasis or the process of maintaining the internal environment of the body, the nutrients which could be the molecules or ions move from the region of high concentration or amount to a region of their low concentration through the cell membrane.

The concentration of calcium inside the cells during homeostasis is maintained by the diffusion of the calcium ions. Thus, option-D is the correct answer.

krok68 [10]3 years ago
7 0
Hello there! 

I believe "<span>b. Nutrients move from an area of lower concentration to an area of higher concentration." is correct!

Have a cool day! -Wajiha</span>
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A hot-water stream at 70°C enters an adiabatic mixing chamber with a mass flow rate of 3.6 kg/s, where it is mixed with a stream
cupoosta [38]

Answer:

a) 4.58 kg/s

b) 0.105 kW/K

Explanation:

a) For the energy balance

qin = qout

min*cin*Tin = mout*cout*Tout

Where min is the mass flow that is entering the system, cin is the specific heat of the substance that is entering, Tin is the temperature of the substance that is entering, and the out is from the substances that are leaving the system. Because there is only water in the system cin = cout. The energy balance will be then:

mh*Th + mc*Tc = (mh + mc)*Tmix

Where h is from the hot water, c is from the cold water, and mix for the mixture that leaves the chamber. Th = 70ºC + 273 = 343 K, Tc = 20ºC + 273 = 293 K, Tmix = 42ºC + 273 = 315 K

3.6*343 + mc*293 = (3.6 + mc)*315

293mc - 315mc = 3.6*315 - 3.6*343

- mc*(315 - 293) = -3.6*(343 - 315)

mc = 3.6*(343 - 315)/(315 - 293)

mc = 3.6*28/22

mc = 4.58 kg/s

b) The entropy balance is:

Sin + Sout - Sgen = ΔSsystem

Where Sin is the entropy of the entering substances, Sout the entropy that the leaving substances, and Sgen the entropy that is generated in the process.

The entropy variantion for an adiabatic process is 0, so ΔSsystem = 0

Sgen = Sin + Sout

The sum of entropy is:

m*cp*ln(Tfinal/Tinitial), where cp is the specific heat (4.184 kJ/kg.K)

Sgen = mc*cp*ln(Tmix/Tc) + mh*cp*ln(Tmix/th)

Sgen = 4.58*4.184*ln(315/293) + 3.6*4.184*ln(315/343)

Sgen = 1.3874 + (-1.2827)

Sgen = 0.105 kW/K

5 0
3 years ago
How would you describe the particles that make up a liquid? are the shape and volume of liquids definite or indefinite?
olga55 [171]
Particles in a liquid move freely and liquids have a definite volume and indefinite shape since it occupies the shape of the container in which the liquid is in.
7 0
3 years ago
What is the capacity to do work known as?
Jlenok [28]
Energy

Simply Energy.
5 0
2 years ago
Read 2 more answers
Determine what is missing from this neutralization reaction: AgNO3+KCl→AgCl+−−−−
lapo4ka [179]

Answer:

The answer to your question is: KNO₃

Explanation:

                                AgNO3  +  KCl   →   AgCl  +   −−−−

A. KNO3    this option is correct because it is a double replacement reaction then potassium must attached to NO₃.

B. KOH  this product is not possible because there is no water to form OH⁻ ions.

C. Ag2K  this product is not possible because both Ag and K are metals, then it is difficult that they attach.

D. KN2O This product is imposible to form, this option is wrong.

7 0
2 years ago
(a) 4.12 x 10^15 atoms U
DochEvi [55]

Answer:

1.63ₓ10⁻⁶ g of U

139.03 g of H

0.385 g of O

141.8 g of Pb

Explanation:

In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles

Therefore:

4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U

8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H

1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O

4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb

Moles . Molar mass = Mass (g)

6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U

139.03 moles of H . 1 g/mol = 139.03 g of H

0.0241 moles of O . 16 g/mol = 0.385 g of O

0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb

8 0
3 years ago
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