The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.
Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).
Nomenclature:
In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.
Name of Formate:
Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.
E.g.
HCOOH (formic acid) → HCOO⁻ (formate) + H⁺
H₃CCOOH (acetic acid) → H₃CCOO⁻ (acetate) + H⁺
Formal Charges:
Formal charges are calculated using following formula,
F.C = [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]
For Oxygen:
F.C = [6] - [6 + 2/2]
F.C = [6] - [6 + 1]
F.C = 6 - 7
F.C = -1
For Sodium:
F.C = [1] - [0 + 0/2]
F.C = [1] - [0]
F.C = 1 - 0
F.C = +1
Answer:
6) λ = 0.84 × 10⁻⁸ m
7) λ = 0.84 × 10⁻⁶ m
Explanation:
6) Given data:
Wavelength of photon = ?
Frequency of photon = 3.56 × 10¹⁶ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 3.56 × 10¹⁶ Hz × λ
λ = 3×10⁸ m/s / 3.56 × 10¹⁶ s⁻¹
λ = 0.84 × 10⁻⁸ m
7) Given data:
Wavelength of photon = ?
Frequency of photon = 6.15 × 10¹⁴ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 6.15 × 10¹⁴ Hz × λ
λ = 3×10⁸ m/s / 6.15 × 10¹⁴ Hz s⁻¹
λ = 0.84 × 10⁻⁶ m
<span>Halflife is the time needed for a radioactive molecule to decay half of its current mass. If t is the time elapsed, the formula for the halflife would be:
final mass= original mass * </span>

<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass *

final mass= 800g *