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dmitriy555 [2]
3 years ago
11

Which does not affect the rate of pulmonary and systemic gas exchange?

Chemistry
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:b

Explanation:

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Propane, C3H8, consists of ________________ bonds and it can be expected to dissolve in hexane and to not dissolve in water.
PtichkaEL [24]

Non-polar covalent

Explanation:

Propane is made up of non-polar covalent bonds and it can be expected to dissolve in hexane and to not dissolve in water.

Propane is an hydrocarbon gas.

It forms by sharing of electrons between two atoms with very low electronegativity differences.

This differences results in equal sharing of the shared electron. Therefore they form a non-polar covalent bond.

Water is a polar covalent compound and cannot dissolve compounds that are not polar like propane.

Propane will only dissolve in a like substance like hexane which is equally non-polar.

learn more:

Covalent compounds brainly.com/question/3109255

#learnwithBrainly

4 0
3 years ago
The pressure on a sample of gas is increased from 1.0 atm to 3.0 atm. If the new volume is 0.52 L, find the original volume.
swat32

Answer: 1.56 ATM

Explanation: if we assume temperature is constant, gas obeys

Boyles law pV= constant. Then p1·V1= p2·V2. And V1 = p2V2/p1

= 3.0 atm·0,52 l / 1.0 atm

3 0
3 years ago
Predict how many antacid tablets it would take to produce 120 mL of CO2 gas
Alja [10]
<span>The question does not mention the brand or size of antacid tablets, but some research in the internet shows that for a very common brand, Alka Seltzer, that it takes about 4 tablets to produces 60 mL of gas. So for 120mL it will take 120/60 x 4 or 8 tablets to produce 120 mL of CO2 gas.</span>
7 0
3 years ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
A student prepares an iron standard solution in a 50.00 mL volumetric flask. The iron stock concentration is 0.0001974 M. A stud
Serhud [2]

Answer:

0.00011765 M

Explanation:

When a solution is prepared by dilution, the volumes and concentrations are related by:

C1*V1 = C2*V2

Where C1 is the concentration of the solution 1, V1 is the volume of the solution 1, C2 is the concentration of solution 2, and V2 is the volume of solution 2.

The stock solution is the solution 1, and the standard solution, the solution 2, so:

0.0001974*29.80 = C2*50.00

C2 = 0.00011765 M

4 0
3 years ago
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