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3 years ago

Hich equation correctly applies the distributive property?

1 answer:

8 0

The answer is c. 0.7 is in every set of pairs so you would get the same product by multiplying all of them the way c has it.

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Please help me almost done

Gnom [1K]

Answer:

x = -8

<XCE = 30

Step-by-step explanation:

Remark

In any question like this, there are 8 possible answers. Of the 8, 4 are acute angles and 4 are obtuse. So any pair are either equal to each other, or they are supplementary. In this case the two given angles are equal.

We have a little bit of both in this question.

Solution

3x + 174 = - 7x + 94 Alternate exterior angles. Add 7x to both sides.

3x+7x +174 = 94 Combine

10x + 174 = 94 Subtract 174 from both sides

10x = 94 - 174

10x = - 80 Divide by 10

x = - 80/10

x = - 8

===================

Check

3x + 174 = -24 + 174 = 150

-7x + 94 = -7*-8 + 94

-7x + 94 = 56 + 94 = 150

<XCE

<XCE = 180 - (3x + 174)

<XCE = 180 - (-24 + 174)

<XCE = 180 - (150)

<XCE = 30

3 0

3 years ago

HELPPP PLEASE WILL NAME BRAINLIEST

laila [671]

The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.

The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.

7 0

3 years ago

Read 2 more answers

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0

2 years ago

INCREDIBLY URGENT!

klemol [59]

Answer:

a) By graphing just one interval of length $T$ . b) Infinite number of angles, c) Infinite times.

Step-by-step explanation:

Any function is periodical when:

$f(t) = f(t+i\cdot T)$ , $\forall i \in \mathbb{N}_{O}$

Where $T$ is the period of the function. The periodicity of the function allows us to limit the graphing of the function to just an interval of one period and according to the definition, you can expect same output with n different angles (infinite number of angles and same output infinite times).

4 0

3 years ago

The number of buckets of paint n needed to paint a fence varies directly with the total area of the fence and inversely with the

Vesna [10]

It takes three 1-gallon buckets to paint 72sqft, if you simplify or find the unit rate, you can know that you can paint 24sqft with one 1-gallon bucket of paint. Since you need to paint 90 sqft, you can’t use three buckets because it only covers 72sqft, but if you use 4 buckets, it will cover 96sqft.

THE ANSWER IS 4 1-GALLON BUCKETS OF PAINT

6 0

3 years ago