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Anton [14]
3 years ago
15

Your first day on the job, you get a call from the owner complaining that her network connection is down. A quick check of the c

entral switch verifies that its in good working order, as is the bosss PC. As luck would have it, your supervisor calls at just that time and tells you not to worry; shell be by in a jiffy with her TDR to help root out the problem. What is she talking about?
Physics
1 answer:
mylen [45]3 years ago
8 0

Answer:

TDR means Timeout Detection and Recovery.

Explanation:

TDR is a feature of the Windows operating system which detects response problems from a graphics card, and recovers to a functional desktop by resetting the card. If the operating system does not receive a response from a graphics card within a certain amount of time (default is 2 seconds), the operating system resets the graphics card.

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You create a ramp using two text books and a 0.50m board. Using a timer you determine that a cart can roll down the ramp in 0.55
ahrayia [7]

Answer:

The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.

Explanation:

Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:

v=v_0+at\\\\v^2=v_0^2+2ad

Dividing the second equation by the first one, we obtain:

v=\frac{v_0^2+2ad}{v_0+at}

And, since v_0=0, then:

v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s

It means that the velocity at the bottom of the ramp is 1.81m/s.

We could use this data, plus any of the two initial equations, to determine the acceleration:

v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2

So the acceleration is 3.30m/s^2.

7 0
4 years ago
A mass is placed at the end of a spring. It has starting velocity of V & allowed to oscillate freely. If the mass has a star
LiRa [457]

Answer:

Equation for SHM can be written

V = w A cos w t        where w is the angular frequency and the velocity is a                                         maximum at t = 0

V1 = w1  A cos w1 t

V2 = w2 A cos w2 t

V2 / V1 = w2 / w1     since cos X t = 1 if t = zero

V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2

If the velocity is twice as large the period will be 1/2 long

8 0
3 years ago
These are nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the oz
yarga [219]
Hello! The nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the ozone layer are the Chlorofluorocarbons (CFCs)

These are compounds developed and improved by Thomas Midgley in the late 1920s. They were used as refrigerants and aerosol propellants.

These compounds created a hole in the ozone layer by the following reactions:

CCl₃F → CCl₂F· + Cl· (In the presence of light. Radical Reaction)
Cl· + O₃ → ClO + O₂
ClO + O₃ → Cl· + O₂ 

The last 2 reactions can repeat in a radical mechanism and explain why these compounds are so harmful to the ozone layer. 
4 0
4 years ago
Which of these factors will increase the speed of a sound wave in air?
Artemon [7]
<h3>Answer;</h3>

-Temperature

<h3><u>Explanation;</u></h3>
  • Sound is a type of mechanical wave, which means it requires a material medium for transmission. It results from the vibration of particles.
  • The speed of sound in mediums varies depending on the property of the medium and a number of other factors which includes; temperature, pressure,  and humidity.
  • Temperature increases the speed of sound wave as particles at higher temperatures tend to possess more energy and thus they will vibrate faster and thus the sound wave will travel faster.
3 0
3 years ago
A kettle of water contains 1.2 kg of water. Calculate how much energy is required to hear it from water at 10 degrees to its boi
Darya [45]

Answer:

450 kJ

Explanation:

Q = mCΔT

where Q is heat (energy),

m is mass,

C is specific heat capacity,

and ΔT is the temperature change.

Q = (1.2 kg) (4180 J/kg/°C) (100°C − 10°C)

Q = 451,440 J

Q ≈ 450 kJ

6 0
3 years ago
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