IBM has a computer it calls the Blue Gene/L that can do 136.8 teracalculations per second. How many calculations can it do in a
2 answers:
IBM has a computer it calls the Blue Gene/L that can do calculations in a microsecond or
megacalculations in a microsecond
Conversion of units is the conversion between different units of measurement for the same quantity, typically through multiplicative conversion factors.
There are methods for converting values with multiple units
- Write down your problem.
- Find the conversion for one unit
- Multiply your number by the conversion fraction.
- Cancel out your units.
- Multiply with another conversion fraction the same way.
- Cancel units.
- Repeat until the conversion is done
The seven base quantities and their corresponding units are:
- length (metre)
- mass (kilogram)
- time (second)
- electric current (ampere)
- thermodynamic temperature (kelvin)
- amount of substance (mole)
- luminous intensity (candela)
IBM has a computer it calls the Blue Gene/L that can do 136.8 teracalculations per second. How many calculations can it do in a microsecond?
prefixes : tera =
micro = , there are
microseconds
in 1 second
So, it can do calculations in a microsecond or
megacalculations in a microsecond. The answer is in four significant digits
- Learn more about physics microsecond brainly.com/question/4942348
Grade: 9
Subject: physics
Chapter: microsecond
Keywords: microsecond
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Answer:
-
Explanation:
We are given that
Mass of cars= m=1900 kg
Initial speed of car=u=20 m/s
Final speed of car=v=0
Time==1.3 s
We have to find the average force exerted on the car.
Average force=
Hence, the average force exerted on the car that hits a line of water barrels=-
The expression for the radius and height of the cone can be obtained from
the property of a function at the maximum point.
- The height of the cone is half the length of the radius of the circular sheet metal.
Reasons:
The part used to form the cone = A sector of a circle
The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.
θ/360·2·π·s = 2·π·r
Where;
s = The radius of he circular sheet metal
h = s² - r²
3·r²·s² - 4·r⁴ = 0
3·r²·s² = 4·r⁴
3·s² = 4·r²
Learn more here:
Answer:
a) L = 3.29 10⁻⁴ H, b)U = 5.33 10⁻² J
Explanation:
a) The inductance is a solenoid this given carrier
L =
The magnetic field inside the solenoid is
B = μ₀
hence the magnetic flux
Ф_B = B. A = μ₀
we substitute in the expression of inductance
L = N² μ₀ A /l
let's find the area of each turn
A = π r²
A = π 0.02²
A = 1.2566 10⁻³ m²
let's calculate
L = 250² 4π 10⁻⁷ 1.2566 10⁻² / 0.3
L = 3.29 10⁻⁴ H
b) The stored energy is
U = ½ L i²
let's calculate
U = ½ 3.29 10⁻⁴ 18²
U = 5.33 10⁻² J