All categories

3 years ago

When looking at a graph what are the first 3 things you should do?

Physics

2 answers:

NNADVOKAT [17]3 years ago

6 0

See if x,y points are negative or positive then write them down

Valentin [98]3 years ago

4 0

Answer: Look where the points are.

Explanation:

You might be interested in

(YOU WILL GET BRAINLIEST)Matter may be classified as a pure substance or a mixture. Where on the Venn diagram would you insert t

inessss [21]

I think it would be B because it is matter, since it has atoms, and it contains subatomic particles, which are smaller than atoms

3 0

3 years ago

Read 2 more answers

17. A household installs solar panels and captures more energy than it consumes. However, their peak energ

padilas [110]

Answer:

battries

Explanation:

4 0

3 years ago

A softball is thrown from the origin of an x-y coordinate system with an initial speed of 18m/s at an angle of 35 degrees above

Bond [772]

Distance = speed × time

After 0.5s , horizontal distance covered is 0.5s × 18m/s = 9m

9m/ y position = cos 35° , y position = 9 ÷ cos 35° = 10.9870m (rounded up to nearest four decimal places)

After t = 1.0s:

Horizontal distance = 18m/s × 1.0s = 18m

y position = $\frac{18m}{cos 35°}$ = 21.9740m (rounded up to nearest four decimal places)

After t = 1.5s:

Horizontal distance = 18m/s × 1.5s = 27m

y position = $\frac{27}{cos 35°}$ = 32.9709m (rounded up to nearest four decimal places)

After time is 2.0s:

Horizontal distance = 18m/s × 2.0s = 36m

y position = $\frac{36}{cos 35°}$ = 43.9479m (rounded up to nearest four decimal places)

3 0

4 years ago

If the releases 39.4 kj of energy, how many kilocalories does it release? (1 cal = 4.184 j) (round off answer to 2 decimal place

REY [17]

By using unit conversion, the energy released in kilocalories is 9.42 kcal.

We need to know about unit conversion to solve this problem. There are several energy units which able to explain how much the energy is such as calories and joule. The energy unit can be converted to another unit by unit conversion. The unit conversion of calorie to joule is

1 cal = 4.184 joule

From the question above, we know that

E = 39.4 kJ

By using the unit conversion, we can convert the energy into calorie

E = 39.4 kJ

E = 39.4 x 10³ J

E = 39.4 x 10³ / 4.184 cal

E = 9.42 x 10³ cal

E = 9.42 x 10³ /10³ kcal

E = 9.42 kcal

Hence, the energy released in kilocalories is 9.42 kcal.

Find more on unit conversion at: brainly.com/question/141163

#SPJ4

8 0

2 years ago

An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a

IgorLugansk [536]

Answer:

The de Broglie wavelength of electron βe = 2.443422 × 10⁻⁹ m

The de Broglie wavelength of proton βp = 5.70 × 10⁻¹¹ m

Explanation:

Thermal kinetic energy of electron or proton = KE

∴ KE = 3kbT/2

given that; kb = 1.38 x 10⁻²³ J/K , T = 1950 K

so we substitute

KE = ( 3 × 1.38 x 10⁻²³ × 1950 ) / 2

kE = 4.0365 × 10⁻²⁰ ( is the kinetic energy for both electron and proton at temperature T )

Now we know that

mass of electron M'e = 9.109 × 10⁻³¹

mass of proton M'p = 1.6726 × 10⁻²⁷

We also know that

KE = p₂ / 2m

from the equation, p = √ (2mKE)

{ p is momentum, m is mass }

de Broglie wavelength = β

so β = h / p = h / √ (2mKE)

h = Planck's constant = 6.626 × 10⁻³⁴

∴ βe = h / √ (2m'e × KE)

βe = 6.626 × 10⁻³⁴ / √ (2 × 9.109 × 10⁻³¹ × 4.0365 × 10⁻²⁰ )

βe = 6.626 × 10⁻³⁴ / √ 7.3536957 × 10⁻⁵⁰

βe = 6.626 × 10⁻³⁴ / 2.71176984642871 × 10⁻²⁵

βe = 2.443422 × 10⁻⁹ m

βp = h / √ (2m'p ×KE)

βp = 6.626 × 10⁻³⁴ / √ (2 × 1.6726 × 10⁻²⁷ × 4.0365 × 10⁻²⁰ )

βp = 6.626 × 10⁻³⁴ / √ 1.35028998 × 10⁻⁴⁶

βp = 6.626 × 10⁻³⁴ / 1.16201978468527 × 10⁻²³

βp = 5.702140 × 10⁻¹¹ m

3 0

3 years ago