Answer : The temperature for non-catalyzed reaction needed will be 456 K
Explanation :
Activation energy : The energy required to initiate the reaction is known as activation energy.
According to the Arrhenius equation,

Since, the rate for both the reaction are equal.


..........(1)
where,
= activation energy for non-catalyzed reaction = 75 kJ/mol
= activation energy for catalyzed reaction = 49 kJ/mol
= temperature for non-catalyzed reaction = ?
= temperature for catalyzed reaction = 
Now put all the given values in the above formula 1, we get:



Therefore, the temperature for non-catalyzed reaction needed will be 456 K
1) Chemical reaction: CH₄ + H₂O → 3H₂ + CO ΔH = + 206 kJ/mol.
2) Chemical reaction: CO + H₂O → CO₂ + H₂, ΔH = + 2,8 kJ/mol.
3) Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O ΔH = -802 kJ/mol.
4) Chemical reaction: 2H₂ + O₂ → 2H₂O ΔH = 2·(-242 kJ7mol) = - 484 kJ/mol.
Endothermic reaction (ΔH>o) and exothermic reaction (ΔH<span><0).</span>
Answer:
The answer to your question is below
Explanation:
I just write the formulas of the reactants and products and balanced the reactions.
a)
3H₂(g) + N₂(g) ⇒ 2NH₃
b)
2K + 2H₂O ⇒ 2KOH + H₂ (g)
c)
2Al(s) + Fe₂O₃ ⇒ Al₂O₃ + 2Fe
d)
Fe₂O₃ + 2Al ⇒ Al₂O₃ + 2Fe
e)
Ba(OH)₂ + 2HBr ⇒ BaBr₂ + 2H₂O
f)
CaCO₃ + Δ ⇒ CaO + CO₂
Answer:
167,3 grams of O2 (g)
Explanation:
According to the following balanced equation:
C3H8 + 5 02 ---> 3 CO2 + 4 H20
We calculate the mass of the moles:
5 mol O2 = 16grams/mol x2x 5= 160 grams/mol
1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol
If 44 grams C3H8 react with--------- 160 grams O2
46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2
Answer:
False. One mole of a certain substance will always contain
atoms of that substance.
Explanation:
Hope this helped!