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makvit [3.9K]
3 years ago
14

In the mid-1900s, most scientists used the Bohr atomic model to study atoms. In the Bohr model, electrons move in set paths arou

nd the atom's nucleus.
In current atomic models, electron clouds are shown around the atom's nucleus. Electron clouds are regions where electrons are likely to be found.

What is a limitation of current atomic models as compared to the Bohr atomic model?

A. Current atomic models do not indicate the position of the nucleus within the atom's structure.

B. Current atomic models do not show how many electrons an atom has.

C. Current atomic models do not show where the electron is but only where the electron is likely to be.
Chemistry
2 answers:
patriot [66]3 years ago
7 0

Answer:

The answer is C.

Explanation:

Novosadov [1.4K]3 years ago
5 0
The answer is c beca it true
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Explanation:

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On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

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Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.
Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

HCOOH\leftrightarrow H^++HCOO^-

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}

1.8*10^-^4=\frac{x^2}{c-x}

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

1.8*10^-^4=\frac{x^2}{0.12}

Let's solve this for x. Multiply both sides by 0.12

2.16*10^-^5=x^2

taking square root to both sides:

x=0.00465

Now, we have got the concentration of [H^+] .

[H^+] = 0.00465 M

We know that, pH=-log[H^+]

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

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